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Misha Larkins [42]
3 years ago
6

3. If you roll a ball up a hill, it undergoes positiveacceleration. True or false​

Physics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

true

Explanation:

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A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal
Masteriza [31]

1) Answer D not at all

The car is not experiencing any frictional force so that implies that there is no force acting on the car once it starts motion. So, according law of inertia, the car will continue to move and no other force is required.

Friction force is the resistance force that opposes the motion of any object. It arises due to the contact of surfaces.

2) Answer C none

There is no force on any spaceship moving far from any planet. So, according to law of inertia the spacecraft will continue to move at same speed.

Law of inertia states that any object keeps in the state of motion or rest unless a non zero external force is applied on it.

6 0
3 years ago
Read 2 more answers
A push or a pull is called _____. User: The metric unit of force is the _____.
Ahat [919]
Force
Newton, abbreviated as N
7 0
3 years ago
The moon Ariel orbits Uranus at a distance of 1.91 x 108 m once every 2.52 days. Use that data to calculate the mass of Uranus.
PIT_PIT [208]

Mu = 8.66 × 10^25 kg

Explanation:

centripetal force = gravitational force

m \frac{ {v}^{2} }{r}  = (grav.const) \frac{m \times mu}{ {r}^{2} }

where

m = mass of moon Ariel

mu = mass of Uranus

r = radius of Ariel's orbit

v = Ariel's velocity around Uranus

To find the velocity, we need to find the circumference of the no orbit and then divide it by the period (2.52 days):

circumference = 2πr = 2π×(1.91 × 10^8 m)

= 1.2 × 10^9 m

period = 2.52 days × (24 h/1 day)×(3600 s/1 hr)

= 2.18 × 10^5 s

v = (1.2 × 10^9 m)/(2.18 × 10^5 s)

= 5.5 × 10^3 m/s

(5.5 × 10^3 m/s)^2/(1.91 × 10^8 m) = (6.67 × 10^-11 m^3/kg-s^2)Mu/(1.91 × 10^8 m)^2

Solving Mu,

Mu = 8.66 × 10^25 kg

4 0
3 years ago
Which one is the lunar eclipse?​
lubasha [3.4K]

Answer:

Yes it would be a lunar eclipse here is an image that I found that might help but during a lunar eclipse when the moon is directly behind earth it will be a full moon

Explanation:

8 0
3 years ago
A centripetal-acceleration addict rides in uniform circular motion with period T = 2.0 s and radius r = 3.00 m. At t1 his accele
Dmitry_Shevchenko [17]

centripetal acceleration always points  towards the center of the circular path and velocity of object in circular motion always points towards the tangent on the the circle in this way centripetal acceleration and velocity are perpendicular to each other and the dot product of  perpendicular vectors is always zero,

therefore v•a=vacosα...........(1)

here α is angle between centripetal acceleration and velocity which is 90

therfore,

From equation (1)

v.a= vacos90

v.a=vax0..............(because cos90=0)

v.a=0 m^2

centripetal acceleration vector points towards center  it means it point towards inwards direction, so it lies along the radius vector,and radius vector points towards outward direction of the circle in this way centripetal acceleration and radius vector are in exact opposite direction so angle between them is 180 degree,

therefore r x a = rasin180

rxa=rax0            (because sin180=0)

rxa=0m^2/s^2 .

6 0
3 years ago
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