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3 years ago

How many protons are in an atom of copper?

Physics

2 answers:

denis-greek [22]3 years ago

5 0

Answer:

Atomic number of copper is 29. The atomic number of an atom is determined by the number of protons in the nucleus. Therefore, there are 29 protons in an atom of copper. In a neutral atom, there are equal number of protons and electrons. Therefore, there are 29 electrons in a copper atom. Mass number of copper is 64.

Number of protons + Number of neutrons = mass number.

Therefore, number of neutrons = 63 -29 = 35

baherus [9]3 years ago

3 0

Answer: Copper (Cu)

Neutrons‎: ‎35 Electrons‎: ‎29

Protons‎: ‎29 Atomic Number‎: ‎29

Explanation:

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A cylinder with rotational inertia I1 = 3.0 kg · m2 rotates clockwise about a vertical axis through its center with angular spee

erastova [34]

Answer:

ω = 1.83 rad/s clockwise

Explanation:

We are given:

I1 = 3.0kg.m2

ω1 = -5.4rad/s (clockwise being negative)

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ω2 = 6.4rad/s (counterclockwise being positive)

By conservation of the momentum:

I1 * ω1 + I2 * ω2 = (I1 + I2) * ω

Solving for ω:

$\omega = \frac{I1 * \omega1 + I2*\omega2}{I1+I2}=-1.83rad/s$

Since it is negative, the direction is clockwise.

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2 years ago

In your own words, explain how solar heating works

mestny [16]

Answer:

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4 0

3 years ago

Read 2 more answers

A conversion factor is a ratio with a value of

Nikitich [7]

The answer would be
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3 years ago

A cube of side 5.0m is in a region where the electric field is directed outward from both of two opposite cube faces, with unifo

guajiro [1.7K]

Answer:

The charge inside the cube is null.

Explanation:

If we apply the gauss theorem with a cubical gaussian surface of the size of the cube:

$\displaystyle\oint_{S} \vec{E}\,\vec{ds}=\frac{q_{in}}{\varepsilon_{0}}$

If we consider than the direction of the electric field is $\vec{E}=E_0\hat{x}$ , we can solve the problem differentiating the integral for each face of the cube:

$\displaystyle\oint_{S} \vec{E}\,\vec{ds}=\displaystyle\int_{S_1} \vec{E}\,\vec{ds_1}+\displaystyle\int_{S_2} \vec{E}\,\vec{ds_2}+\displaystyle\int_{S_3} \vec{E}\,\vec{ds_3}+\displaystyle\int_{S_4} \vec{E}\,\vec{ds_4}+\displaystyle\int_{S_5} \vec{E}\,\vec{ds_5}+\displaystyle\int_{S_6} \vec{E}\,\vec{ds_6}$

$\displaystyle\oint_{S} \vec{E}\,\vec{ds}=\displaystyle\int_{S_1} E_0\hat{x}\,\hat{x}ds_1+\displaystyle\int_{S_2} E_0\hat{x}\,\hat{-x}ds_2+\displaystyle\int_{S_3} E_0\hat{x}\,\hat{y}ds_3+\displaystyle\int_{S_4} E_0\hat{x}\,\hat{-y}ds_4+\displaystyle\int_{S_5} E_0\hat{x}\,\hat{z}ds_5+\displaystyle\int_{S_6} E_0\hat{x}\,\hat{-z}ds_6$