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Greeley [361]
3 years ago
11

A parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates. A 1.0 g plastic bead, with a charg

e of -6.0 nC, is suspended between the two plates by the force of the electric field between them.
Required:
a. Which plate, the upper or the lower, is positively charged?
b. What is the charges on positvie plate?
Physics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

Please find the answer in the explanation

Explanation:

Given that A 1.0 g plastic bead, with a charge of -6.0 nC, is suspended between the two plates by the force of the electric field between them.

Since it is suspended, it must have been repelled by the bottom negative plate and trying to be attracted to the top plate.

We can therefore conclude that the upper plate, is positively charged

B.) The charge on the positive plate of parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates must be less than 6.0 nC

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The color of light emitted by a hot, solid object depends on ______.
nadya68 [22]

Answer:

The correct option is (A).

Explanation:

When the temperature of the hot solid object increases then the radiation which emits from it gets shifted to smaller wavelength or higher frequencies. The hot appears red color.

The total energy emitted of a hot solid object is directly proportional to the fourth power of the temperature of the black body.

For example, when we switch on the light bulb, initially the radiation of the bulb appears dimmer. Then, it will become brighter. Then, it will turn yellow and then it becomes even white.

The color of the light emitted by a hot solid object depends on the temperature of the object.

Therefore, the correct option is (A).

4 0
3 years ago
A car starts from rest at the top of a hill with 45 J of gravitational
kherson [118]

Answer:

<em>The car will be moving at 5.48 m/s at the bottom of the hill</em>

Explanation:

<u>Principle of Conservation of Mechanical Energy</u>

In the absence of friction, the total mechanical energy is conserved. That means that

E_m=U+K is constant, being U the potential energy and K the kinetic energy

U=mgh

\displaystyle K=\frac{mv^2}{2}

When the car is at the top of the hill, its speed is 0, but its height h should be enough to produce the needed speed v down the hill.

The Kinetic energy is then, zero. When the car gets enough speed we assume it is achieved at ground level, so the potential energy runs out to zero but the Kinetic is at max. So the initial potential energy is transformed into kinetic energy.

We are given the initial potential energy U=45 J. It all is transformed to kinetic energy at the bottom of the hill, thus:

\displaystyle \frac{mv^2}{2}=45

Multiplying by 2:

\displaystyle mv^2=90

Dividing by m:

\displaystyle v^2=\frac{90}{m}

Taking square roots:

\displaystyle v=\sqrt{\frac{90}{m}}

\displaystyle v=\sqrt{\frac{90}{3}}

v=\sqrt{30}

v = 5.48 m/s

The car will be moving at 5.48 m/s at the bottom of the hill

3 0
3 years ago
A truck heading east has an initial velocity of 6 m/s. It accelerates at 2 m/s2 for 12 seconds. What distance does the truck tra
gavmur [86]
I believe it would be 144 m!
7 0
3 years ago
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3 years ago
Pilings are driven into the ground at a building site by dropping a 2250 kg object onto them. What change in gravitational poten
den301095 [7]

Answer: 324.135 kJ

Explanation:

Given

Mass of dropping is m=2250\ kg

The initial height of dropping is h_1=16\ m

The final height of dropping h_2=1.3\ m

Gravitational potential energy is the function of height i.e.

\Rightarrow \text{G.E.}=mgh

Change in Gravitational Energy is

\Rightarrow \Delta \text{G.E.}=mg(h_1-h_2)=2250\times 9.8\times (16-1.3)\\\\\Rightarrow \Delta \text{G.E.}=3,24,135\ J\approx 324.135\ kJ

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3 years ago
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