Question

An all-electric home uses approximately 1760 kWh of electric energy per month. How much uranium-235 would be required to provide this house with its energy needs for one year? Assume 100% conversion efficiency and 208 MeV released per fission.

Answer 1

Answer:

mass of U 235 is 8.92 × $10^{-4}$ gram

Explanation:

given data

electric energy = 1760 kWh per month

energy u 235 = 208 MeV

to find out

mass of u 235

solution

we know here energy consume in a year is

energy consume = 1760 × 10³ ×3600 × 12

energy consume = 7.603 × $10^{10}$ J

and

now we find no of u235 atom by burn require energy is

that is = energy consume / energy

= 7.603 × $10^{10}$ / ( 208 × 1.6 × $10^{-13}$ )

= 2.285 × $10^{18}$

and we know 1 mole of  u235 = 6.02 × $10^{23}$ atoms

so mass of U235 is

mass = 2.285 × $10^{18}$  /   ( 6.02 × $10^{23}$ )

mass of U 235 = 8.92 × $10^{-4}$ gram