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hammer [34]
3 years ago
13

Two square coils (1 and 2) of different size but with the same number of turns and carrying the same current are placed in diffe

rent magnetic fields but experience the same maximum torque. If each side of coil 1 is 4.80 cm and it rotates in a 0.18-T field, determine the length of each side of coil 2 if it rotates in a magnetic field of 0.42 T.
Physics
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

idk

Explanation:

i am dumb

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Alguien sabe como resolver esto? no entiendo.
lorasvet [3.4K]

Answer:

THWB WB  WQI B BW W;QQ QY G VQ Q VQVY VAV  G UQ U

Explanation:QCGQ   G GQUIGI QGUI; V AYDFYAFQAVAVY,

3 0
3 years ago
Paul’s 10 kg baby sister Susan sits on a mat. Paul pulls the mat across the floor using a rope that is angled 30° above the floo
kiruha [24]

Answer:

The speed of Susan is 2.37 m/s

Explanation:

To visualize better this problem, we need to draw a free body diagram.

the work is defined as:

W=F*d*cos(\theta)

here we have the work done by Paul and the friction force, so:

W_p=F_p*d*cos(0)\\F_p=30N*cos(30^o)=26N\\W_p=26*3*(1)=78J

W_f=F_f*d*cos(180)\\F_f=\µ*(10*9.8-30N*sin(30^o))=16.6N\\W_p=16.6*3*(-1)=50J

Now the change of energy is:

W_p-W_f=\frac{1}{2}m*v^2\\v=\sqrt{\frac{2(78J-50J)}{10kg}}\\v=2.37m/s

4 0
3 years ago
Read 2 more answers
You find it takes 200 N of horizontal force tomove an unloaded pickup truck along a level road at a speed of2.4 m/s. You then lo
IgorC [24]

ANSWER:

F(h)= 230 N is the horizontal force you will need to move the pickup along the same road at the same speed.

STEP-BY-STEP EXPLANATION:

F(h) is Horizontal Force = 200 N

V is Speed = 2.4 m/s

The total weight increase by 42%

coefficient of rolling friction decrease by 19%

Since the velocity is constant so acceleration is zero; a=0

Now the horizontal force required to move the pickup is equal to the frictional force.

F(h) = F(f)

F(h) = mg* u

m is mass

g is gravitational acceleration = 9.8 m/s^2

200 = mg*u

Since weight increases by 42% and friction coefficient decreases by 19%

New weight = 1+0.42 = 1.42 = (1.42*m*g)

New friction coefficient = μ = 1 - 0.19 = 0.81 = 0.81 u

F(h) = (0.81μ) (1.42 m g)

       = (0.81) (1.42) (μ m g)

       = (0.81) (1.42) (200)

       = 230 N

4 0
3 years ago
Which law states that absolute zero cannot be reached?
Lera25 [3.4K]
Assuming you mean temperature

Answer: The third law of thermodynamics
6 0
3 years ago
In calisthenics, the resistance is ultimately provided by __________. A. free weights B. springs and elastic bands C. gravity D.
tangare [24]

Answer:

I think the answer is b am sorry if it is wrong

Explanation:

5 0
3 years ago
Read 2 more answers
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