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Kipish [7]
3 years ago
10

When do surface waves reach land​

Physics
2 answers:
Alex_Xolod [135]3 years ago
7 0

Answer:

Surface waves are the kind of waves that occur on the surface of the ocean. The reason behind their occurrence is the geological effects, usually in the form of winds in near geographical regions or in that region.

These waves reach the land when the geological winds give a push to the waves and they travel miles and finally hit the land. These waves range in sizes, for small sizes to the the size of tsunami.

fiasKO [112]3 years ago
3 0

Answer with Explanation:

"Surface waves" are also known as <em>"wind-generated waves." </em>Such waves occur on the surface of the water that has a<u> zero parallel shear stress.</u> Their speed upon reaching the land will depend upon the<em> wind blowing over the fluid's surface.</em> So, this means that they could travel several miles before actually reaching the land. They could also come in different sizes, from <em>small ripples</em> to <em>big tsunamis. </em>

The factors that tell the time when the surface waves reach the land are: <em>wind speed, depth of the water, wind duration, the area that is affected by the fetch (width) and the uninterrupted distance of open water.</em>

<em />

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Answer: heat engine

Explanation:

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Ben Rushin is waiting at a stop light. Turns green, ben accelerated from rest at a rate of 6.00 m/s squared for a time of 4.10 s
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3 years ago
2. the dipole moment of a dipole in a 300-n/c electric field is initially perpendicular to the field, but it rotates so it is in
aleksandr82 [10.1K]

Work Done (W) by the field is-6x 107 J,

<h3>What is Electric dipole?</h3>

A pair of opposite, non-coplanar, equally powerful electric charges that are in opposition to one another. An atom is said to have a "induced electric dipole" if the center of the negative cloud of electrons has moved a little bit away from the nucleus due to an external electric field. When the external field is taken away, dipolarity is lost.

Electric field (E) = 300 N/C

Dipole moment (p) = 2 x 10° Cm

Solution:

From the formula we know.

U = -pE cosФ

Here,

p Denotes Dipole moment.

E Denotes Electric field.

Ф Denotes angle b/w them

Now, as given, firstly the dipole is perpendicular to the electric field, so

angle (Ф1) will be 90° and now the dipole is rotated such that they are in same

direction so the angle (Ф2) will be 0°

So, let's find Change in Potential energy which will be equal to the work done

by the electric field.

ΔU = Uf - Ui

ΔU = [-pE*cos Ф2] - [-pE *cos Ф1]

ΔU = [-pE*cos Ф2] + pE *cos Ф1

ΔU = pE * [cos Ф2+ cos Ф1]

Substituting the values,

ΔU = pE * [cos 0° + cos 90°]

ΔU = pE * (-1 +0)

ΔU = -pE

ΔU = -2x 10^-9 × 300

ΔU = 6 x 10^(-9+2)

ΔU = 6 x 10^-7

W = ΔU = -6 x 10^-7

W = - 6 x 10 7 J

Work Done (W) by the field is - 6 x 10-7 J.

To learn more about Work Done visit:

https://brainly.in/question/48222628

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6 0
2 years ago
A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?
irakobra [83]

Answer:

1.2 amps :)

Explanation:

A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?

         Known:

  • R = 10.0 Ω                            
  • V = 12.0 V

       Unknown:

  • I = ???

I = V/R

= 12.0 V / 10.0 Ω

= 1.2 amps

6 0
3 years ago
A horse has an acceleration of 2 m/s2. If it starts from rest, how fast is it going after 1.7 seconds?
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       (2  m/s²)  ·  (1.7  s)  =  3.4 m/s
6 0
3 years ago
Read 2 more answers
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