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Kipish [7]
3 years ago
10

When do surface waves reach land​

Physics
2 answers:
Alex_Xolod [135]3 years ago
7 0

Answer:

Surface waves are the kind of waves that occur on the surface of the ocean. The reason behind their occurrence is the geological effects, usually in the form of winds in near geographical regions or in that region.

These waves reach the land when the geological winds give a push to the waves and they travel miles and finally hit the land. These waves range in sizes, for small sizes to the the size of tsunami.

fiasKO [112]3 years ago
3 0

Answer with Explanation:

"Surface waves" are also known as <em>"wind-generated waves." </em>Such waves occur on the surface of the water that has a<u> zero parallel shear stress.</u> Their speed upon reaching the land will depend upon the<em> wind blowing over the fluid's surface.</em> So, this means that they could travel several miles before actually reaching the land. They could also come in different sizes, from <em>small ripples</em> to <em>big tsunamis. </em>

The factors that tell the time when the surface waves reach the land are: <em>wind speed, depth of the water, wind duration, the area that is affected by the fetch (width) and the uninterrupted distance of open water.</em>

<em />

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Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

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Given that:

the charge (q) = 33.3 nC/m

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a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

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E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

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