<span>Let's assume
that the oxygen gas has ideal gas behavior.
Then we can use ideal gas formula,
PV = nRT</span>
Where, P is the pressure of the gas (Pa), V is the volume of the gas
(m³), n is the number of moles of gas (mol), R is the universal gas
constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.
<span>
P = 2.2 atm = 222915 Pa
V = 21 L = 21 x 10</span>⁻³ m³
n = ?
R = 8.314 J mol⁻¹ K⁻¹
<span>
T = 87 °C = 360 K
By substitution,
</span>222915 Pa x 21 x 10⁻³ m³ = n x 8.314 J mol⁻¹ K⁻<span>¹ x 360 K
n
= 1.56</span><span> mol</span>
<span>
Hence, 1.56 moles of the oxygen gas are </span><span>
left for you to breath.</span><span>
</span>
☁️ Answer ☁️
Thats called weathering.
Weathering describes the breaking down or dissolving of rocks and minerals on the surface of the Earth.
Hope it helps.
Have a nice day noona/hyung!~ ￣▽￣❤️
It would be the controlled variable, which is a baseline to compare your other variables too.
Hope this helps!
Answer:
B. pOH = 14 - pH and D. pH = 14 - pOH.
Explanation:
Hello,
In this case, we must remember that pH and pOH are referred to a measure of acidity and basicity respectively, since pH accounts for the concentration of H⁺ and pOH for the concentration of OH⁻ in a solution. In such a way, since the maximum scale is 14, we say that the addition between the pH and pOH must be 14:
Therefore, the correct answers are B. pOH = 14 - pH and D. pH = 14 - pOH since the both of them are derived from the previous definition.
Best regards.
Answer:
Molar mass of H3PO4 = 97.99 g/mol (Approx.)
Explanation:
Find:
Molar mass of H3PO4
Given;
Molar mass of H = 1.0079 g/mol
Molar mass of P = 30.974 g/mol
Molar mass of O = 15.999 g/mol
Computation:
Molar mass of H3PO4 = (1.0079)(3) + 30.974 + 15.999(4)
Molar mass of H3PO4 = 3.0237 + 30.974 + 63.996
Molar mass of H3PO4 = 97.9937
Molar mass of H3PO4 = 97.99 g/mol (Approx.)
