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Leno4ka [110]
3 years ago
10

In the middle of your Fitness drug you start to feel a little weak selective method of monitoring your Fitness level which would

be readily available to you at the least cost: A. Heart rate monitor B. Pedometer C. Talk test D. Stopwatch
Physics
2 answers:
salantis [7]3 years ago
8 0

Answer:

c

Explanation:

Eva8 [605]3 years ago
7 0

Answer:

C. Talk test

Explanation:

The talk test would be readily available to me at the the least cost.

The talk test is about the easiest way that one can monitor intensity as they exercise. Because the only thing needed here is the ability to talk and to breathe.

The intensity lies on if one can talk and breathe at the same time. The harder one exercises, the more breathless they become and they find it difficult to talk.

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How does what happens to the particles in a substance during melting differ from what happens during freezing?
sasho [114]
When in the melting process particles start to move more freely when in the freezing process particles tend to slow and vibrate in place
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3 years ago
10. What is Newton's 3rd Law?
charle [14.2K]

Answer:

A. For every action there is an equal and opposite reaction.

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2 years ago
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What is the Primacy Effect? Question 1 options:
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So B would be your answer

3 0
4 years ago
A uniform rod rotates in a horizontal plane about a vertical axis through one end. The rod is 3.46 m long, weighs 12.8 N, and ro
Mkey [24]

Answer:

a. Rotational inertia: 5.21kgm²

b. Magnitude of it's angular momentum: 123.32kgm²/s

Explanation:

Length of the rod = 3.46m

Weight of the rod = 12.8 N

Angular velocity of the rod= 226 rev/min

a. Rotational Inertia (I) about its axis

The formula for rotational inertia =

I = (1/12×m×L²) + m × ( L ÷ 2)²

Where L = length of the rod

m = mass of the rod

Mass of the rod is calculated by dividing the weight of the rod with the acceleration due to gravity.

Acceleration due to gravity = 9.81m/s²

Mass of the rod = 12.8N/ 9.81m/s²

Mass of the rod = 1.305kg

Rotational Inertia =

(1/12× 1.305 × 3.46²)+ 1.305 ( 3.46÷2)²

Rotational Inertia =  1.3019115 + 3.9057345

Rotational Inertia = 5.207646kgm²

Approximately = 5.21kgm²

b. The magnitude of the rod's angular momentum about the rotational axis is calculated as

Rotational Inertia about its axis × angular speed of the rod.

Angular speed of the rod is calculated as= (Angular velocity of the rod × 2π)/60

= (226×2π) /60

= 23.67 rad/s

Rotational Inertia = 5.21kgm²

The magnitude of the rod's angular momentum about the rotational axis

= 5.21kgm²× 23.67 rad/s

= 123.3207kgm²/s

Approximately = 123.32kgm²/s

7 0
3 years ago
10 points please somebody help me
Anuta_ua [19.1K]
It is the first one?
7 0
3 years ago
Read 2 more answers
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