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Sav [38]
3 years ago
5

If the voltage in a wire is 10 volts, and the current is 5 amps, what is the resistance in the wire? Show work. Please put units

with it too :) i will mark brainliest

Physics
1 answer:
aniked [119]3 years ago
5 0

Answer:2 ohm

Explanation:

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A car has an acceleration of 1.5 m/s2. A net force of 2100 N is acting on the car. What is the mass of the car?
gulaghasi [49]

Answer:

Given

acceleration (a) =1.5ms2

Force(F) =2100N

R. t. c mass (m) =?

Form

F=ma(divided by m both sides)

m=F/a

m=2100/105

m=1400kg

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Which of Newton's laws says that an object in motion stays in motion, and an object at rest stays at rest unless acted upon by a
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2 years ago
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
kykrilka [37]

Explanation:

It is given that,

Mas of the car, m_1=1170\ kg

Initial speed of the car, u_1=25\ m/s

Mass of the truck, m_2=9800\ kg

Initial speed of the car, u_2=20\ m/s

Final speed of the car, v_1=18\ m/s

(a) It is a case of elastic collision. Let v_2 is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{1170\times 25+9800\times 20-1170\times 18}{9800}

v_2=20.83\ m/s

(b) Initial kinetic energy is given by :

k_i=\dfrac{1}{2}(m_1u_1^2+m_2u_2^2)

k_i=\dfrac{1}{2}\times (1170\times (25)^2+9800\times (20)^2)

k_i=2325625\ J

Final kinetic energy is given by :

k_f=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

k_f=\dfrac{1}{2}\times (1170\times (18)^2+9800\times (20.83)^2)

k_f=2315595.61\ J

The change in mechanical energy of the car truck system in the collision:

\Delta K=k_f-k_i

\Delta K=2315595.61-2325625

\Delta k=-10029.39\ J

The loss in kinetic energy is 10029.39 Joules.

(c) The change in mechanical energy gets changed energy gets changed in the form of heat and light.

Hence, this is the required solution.

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