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Naya [18.7K]
3 years ago
13

__________ is an electronic record of health-related information on an individual that conforms to nationally recognized interop

erability standards and that can be created, managed and consulted by authorized clinicians and staff across more than one healthcare organization.
Physics
2 answers:
Ira Lisetskai [31]3 years ago
6 0

Answer:

Electronic Health Record (EHR)

Explanation:

An Electronic Health Record is basically a digital equivalent of a patient's medical record. They are extremely useful because they provide a concise and accurate history of all of the patient's former treatments, exams and ilnesses, which help in optimization of the treatment process by eliminating extra steps like retaking exams and reducing the odds of medical errors.

Ray Of Light [21]3 years ago
6 0

Answer:

Electronic health record

Explanation:

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Two long parallel wires are separated by 6.0 mm. The current in one of the wires is twice the other current. If the magnitude of
lions [1.4K]

Answer:

Explanation:

Magnitude of force per unit length of wire on each of wires

= μ₀ x 2 i₁ x i₂ / 4π r    where i₁ and i₂ are current in the two wires , r is distance between the two and  μ₀ is permeability .

Putting the values ,

force per unit length = 10⁻⁷ x 2 x i x 2i / ( 6 x 10⁻³ )

= .67 i² x 10⁻⁴

force on 3 m length

= 3 x .67 x 10⁻⁴ i²

Given ,

8 x 10⁻⁶ = 3 x .67 x 10⁻⁴ i²

i²  = 3.98 x 10⁻²

i = 1.995 x 10⁻¹

= .1995

=  0.2 A approx .

2 i = .4 A Ans .

6 0
4 years ago
The mass of a golf ball is 45.9 g . if it leaves the tee with a speed of 62.0 m/s , what is its corresponding wavelength?
inn [45]

The wavelength of the golf ball is <u>2.328×10⁻³⁴m.</u>

All moving particles with mass have a matter wave associated with it. These matter waves are called deBroglie waves.

The deBroglie wavelength λ of a particle is given by,

\lambda=\frac{h}{mv}

Here, h is the Planck's constant, m is the mass of the ball and v is its velocity.

Calculate the deBroglie wavelength of the moving golf ball by substituting 6.626×10⁻³⁴J s for h, 45.9×10⁻³kg for m and 62.0 m/s for v.

\lambda=\frac{h}{mv}\\ =\frac{6.626*10^-^3^4Js}{(45.9*10^-^3kg)(62.0m/s)} \\ =2.328*10^-^3^4m

The wavelength of the golf ball is  <u>2.328×10⁻³⁴m.</u>




4 0
4 years ago
a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel d
trasher [3.6K]
50π m ≈ 157 m
Explanation:
100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s
d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m
8 0
3 years ago
1) What kind of energy is gained when your roller coaster goes uphill?
Dvinal [7]

1) Gravitational potential energy

In fact, gravitational potential energy is given by: GPE=mgh

where m is the mass of the roller coaster, g is the gravitational acceleration and h is the heigth. Therefore, when the roller coaster goes uphill, the height h increases and the roller coaster gains gravitational potential energy.

2) The relationship between potential and kinetic energy is:

M.E.=K.E.+G.P.E.

where ME is the total mechanical energy, KE is the kinetic energy, GPE is the gravitational potential energy. Since the value of ME is constant (when no friction is present), this means that when KE increases, GPE decreases, and vice-versa.

3) If friction is removed from the track, the roller coaster would move forever. In fact, in the equation written in part 2), ME is constant only in case there is no friction - when friction is present, part of the energy is lost due to the friction, so the total ME available decreases little by little until it becomes zero, and the roller coaster cannot move anymore.

4) It matters because it affects the magnitude of the friction. In fact, friction is given by

F=\mu mg

where \mu is the coefficient of friction, m is the mass ,and g the gravitational acceleration. When the number of carts is increased, the mass increases, therefore the friction increases as well.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH THIS ONE QUESTION
Cerrena [4.2K]

Answer:

3.11ev

Explanation:

E = hf

E = 6.626 * 10^-^3^4  *  7.5 * 10^1^4\\E = 49.695 * 10^-^2^0

1ev = 1.60 * 10^-^1^9\\xev = 49.695 * 10^-^2^0 / 1.60 * 10^-^1^9\\xev = 3.1059\\xev = 3.11eV

4 0
3 years ago
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