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dedylja [7]
3 years ago
11

WILL MARK BRAINLIEST

Physics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

152,155 J

Explanation:

115,333 + 36,822 = 152,155J

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Answer: boyles law I’m pretty sure
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The variables for this experiment include mass, volume, and the materials in the various balls and their densities. In Part III,
zmey [24]

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volume and density

Explanation:

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2 years ago
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Why are energy pyramids usually no more than 4 trophic levels?
Sav [38]
There are usually no more than four trophic levels, because of the huge loss of energy at each trophic levels. Alomost 10 percent of the energy is lost at each level, as compared to the previous level, which occurs due to wastage of materials like bones and leftover tissues. So, till the fourth trophic level, very less energy is left to be continued to another level, and thus the process is like that.
4 0
3 years ago
An emf source with emf of 200 V, a resistor with R =50.0 Ω, and a capacitor with C = 4.0 mF are connected in series. As the capa
Gemiola [76]

Answer:

0.6 C

Explanation:

From the question,

Since the Resistor and the capacitor are connected in series.

The voltage across the resistor + Voltage across the capacitor = Total voltage.

Vt = Vr+Vc............... Equation 1

Where Vt = Total voltage, Vr = Voltage across the resistor, Vc = Voltage across the capacitor

make Vc the subject of the equation

Vc = Vt-Vr.............. Equation 2

From ohm's law,

Vr = IR................... equation 3

Where I = current, R = Resistance.

Given: I = 1 A, R = 50 Ω

Substitute into equation 3

Vr = 1(50)

Vr = 50 V

Also given: Vt = 200 V

Substitute into equation 2

Vc = 200-50

Vc = 150 V.

Applying,

Q = CVc..................... Equation 4

Where Q = charge on each plate of the capacitor, C = Capacitance of the capacitor

Given: C = 4.0 mF = 4.0×10⁻³ F, Vc = 150 V

Substitute into equation 4

Q = 4.0×10⁻³(150)

Q = 0.6 C

5 0
3 years ago
Calculate the point of no return for an airport runway of 1.60 mi in length if a jet plane can accelerate at 10.1 ft/s2 and dece
Vilka [71]

Answer:

t = 26.39 s

Explanation:

given,

Length of runway = 1.60 mi = 8448 ft

acceleration of the jet = 10.1 ft/s²

deceleration of the jet = 7.21 ft/s²

Let x be the distance of no return

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 × 10.1 × x

v = √(20.2 x)

now, after reaching that Point the deceleration of the plane start

using equation of motion

final velocity of the first case will be the initial velocity of the second case

v² = u² + 2 a s

0 = 20.2 x - 2 x 7.21 x(8448-x)

34.62 x = 121820.16

x = 3518.78 ft

time taken to reach no return point

x = ut+\dfrac{1}{2}at^2

3518.78 =\dfrac{1}{2}\times 10.1\times t^2

    t² = 696.788

    t = 26.39 s

time taken to reach the no return point is equal to 26.39 s.

8 0
3 years ago
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