Answer:
Potential energy of the object will be equal to mgh
Explanation:
Let the mass of the object is m
Acceleration due to gravity is 
Let the object is released from height h
We have to find the potential energy
Potential energy is of an object released from height h is equal to
, here m is mass, g is acceleration due to gravity and h is height from which object is released.
Answer:
11250 N
Explanation:
From the question given above, the following data were obtained:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
Friction and normal force are related by the following equation:
F = μR
Where:
F is the frictional force.
μ is the coefficient of static friction.
R is the normal force.
With the above formula, we can calculate the frictional force acting on the car as follow:
Normal force (R) = 15000 N
Coefficient of static friction (μ) = 0.75
Frictional force (F) =?
F = μR
F = 0.75 × 15000
F = 11250 N
Therefore, the frictional force acting on the car is 11250 N
Answer:4.08 N
Explanation:
Given data
superball dropped from a height of 10 cm
Mass of ball
=0.05kg
time of contact
=34.3
s
Now we know impulse =
=Change in momentum
=
and velocity at the bottom is given by
v=
=
=4.081N
When air resistance acts, acceleration during a fall will be less than g because air resistance affects the motion of the falling objects by slowing it down. ... Air resistance depends on two important factors - the speed of the object and its surface area.
Answer:
Surface
Explanation:
Rayleigh Waves—surface waves that move in an elliptical motion, producing both a vertical and horizontal component of motion in the direction of wave propagation. Particle motion consists of elliptical motions (generally retrograde elliptical) in the vertical plane and parallel to the direction of propagation.
