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2 years ago

Some gaseous pollutants bond with water to form little droplets known as _________.

1 answer:

defon2 years ago

8 0

The correct choice in the options above is the aerosols. It is because the aerosols are the ones that are combined with gaseous substances and water in order for it to be formed. Without the gaseous substance being joined with the water then the aerosols won't be produced.

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Meiosis goes through 2 divisions to create four unique haploid cells. true or false

Aleksandr [31]

Answer:

True

Explanation:

True is the ANSWER.

7 0

2 years ago

What ion carries two negative charges and is isoelectronic with k+?

lutik1710 [3]

The answer is: " S²⁻ " .
_________________________________________

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2 years ago

Identify the atoms that are oxidized and reduced, the change in the oxidation state for each, and oxidising and reducing agents

KATRIN_1 [288]

Answer:

Explanation:

a) $Mg + NiCl_2 \rightarrow MgCl_2 + Ni$

Oxidation state of Mg changes to 0 to +2.

Oxidation state of Ni changes to +2 to 0.

Oxidation state of Cl does not change.

So, Mg is oxidized, Ni is reduced.

Mg acts as reducing agent and $NiCl_2$ acts as oxidizing agent.

b) $PCl_3 + Cl_2 \rightarrow PCl_5$

Oxidation state of P changes to +3 to +5.

Oxidation state of Cl changes to 0 to -1.

So,

P is oxidized and Cl is reduced.

$PCl_3$ acts as reducing agent and $Cl_2$ acts as oxidizing agent.

c) $C_2H_4 + 3O_2 \rightarrow 2CO_2 + 2H_2O$

Oxidation state of C changes to -2 to +4.

Oxidation state of O changes to 0 to -2.

Oxidation state of H does not change.

So,

C is oxidized and O is reduced.

$C_2H_4$ acts as reducing agent and $O_2$ acts as oxidizing agent.

d) $Zn + H_2SO_4 \rightarrow ZnSO_4 + H_2$

Oxidation state of Zn changes to 0 to +2.

Oxidation state of H changes to +1 to 0.

Oxidation state of S and O do not change.

So, Zn is oxidized, H is reduced.

Zn acts as reducing agent and $H_2SO_4$ acts as oxidizing agent

e) $K_2S_2O_3 + I_2 \rightarrow K_2S_4_O6 + 2KI$

Oxidation state of S changes to +2 to +2.5.

Oxidation state of I changes to 0 to -1.

Oxidation state of K and O do not change.

So, S is oxidized, I is reduced.

$K_2S_2O_3$ acts as reducing agent and $I_2$ acts as oxidizing agent.

f) $3Cu + 8HNO_3 \rightarrow 3Cu(NO_3)_2 + 4H_2O+2NO$

Oxidation state of Cu changes to 0 to +2.

Oxidation state of N changes to N +5 to +2.

Oxidation state of H and O do not change.

So, Cu is oxidized, N is reduced.

Cu acts as reducing agent and $HNO_3$ acts as oxidizing agent

8 0

2 years ago

Drinking energy drinks makes people more aggressive.

ch4aika [34]

Outcome (dependent) variable-drinking energy drinks

Test (independent) variable- more aggressive

7 0

2 years ago

If a chemical reaction such as photosynthesis begins with 6 atoms of carbon C , how many atoms of carbon C should be in the prod

lara [203]

Answer:

Option B. 6 atoms of carbon

Explanation:

In <u><em>any chemical reaction</em></u>, atoms from reactant side and product side must be the same.

This is photosynthesis reaction:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

8 0

3 years ago