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german
4 years ago
12

Examples 36

Chemistry
1 answer:
brilliants [131]4 years ago
5 0

2x = 350- x

3x = 350

x = 350/x

therefore,

x = 116.67cm.

so, (350 - x)cm³ = (350- 166.67)cm³ = 233.33cm³

Hence distance covered by gas A is 116.67cm that by B is 233.33cm

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You are provided with a compound fertilizer, 40-15-10.Calculate the quantity of fertilizer to add to a one hectare field supply
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Answer:

a. 300 Kg of fertilizer

b. 225 Kg of fertilizer

c. 400 Kg of fertilizer

d. 600 Kg of fertilizer

Explanation:

The percentage composition ratio of Nitrogen, Phosphorus and Potassium in a 1 Kg bag of the given fertilizer is 40:15:10.

Therefore a  1 Kg bag contains;

40/100 * 1 Kg = 0.4 Kg of Nitrogen;

15/100 * 1 Kg = 0.15 Kg of phosphorus;

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Quantity of fertilizer required to add to a hectare to supply;

a. Nitrogen at 120 kg/ha = 120/0.4 = 300 Kg of fertilizer

b.. Nitrogen at 90 Kg/ha = 90/0.4 = 225 Kg of fertilizer

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d. Potassium at a rate of 60 kg/ha = 60/0.1 = 600 Kg of fertilizer

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Read 2 more answers
A ridged steel tank filled with 62.7L of nitrogen gas of 85.0L atm
mylen [45]

The final gas pressure : 175.53 atm

<h3>Further explanation</h3>

Maybe the complete question is like this :

A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?

The volume remains constant⇒Gay Lussac's Law  

<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature  </em>

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

P₁=85 atm

T₁=19+273=292 K

T₂=330+273=603 K

\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm

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