Someone help me please
1 answer:
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Answer:
E = 12640.78 N/C
Explanation:
In order to calculate the electric field you can use the Gaussian theorem.
Thus, you have:
ФE: electric flux trough the Gaussian surface
Q: net charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2
If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:
r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m
Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:
Finally, you obtain for E:
hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C
Answer:
The value is
Explanation:
From the question we are told that
The initial speed is
Generally the total energy possessed by the space probe when on earth is mathematically represented as
Here is the kinetic energy of the space probe due to its initial speed which is mathematically represented as
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And is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as
Here is the escape velocity from earth which has a value
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Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as
Generally from the law energy conservation we have that
So
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