The total gauge pressure at the bottom of the cylinder would
simply be the sum of the pressure exerted by water and pressure exerted by the
oil.
The formula for calculating pressure in a column is:
P = ρ g h
Where,
P = gauge pressure
ρ = density of the liquid
g = gravitational acceleration
h = height of liquid
Adding the two pressures will give the total:
P total = (ρ g h)_water + (ρ g h)_oil
P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg /
m^3) (9.8 m / s^2) (0.4 - 0.30 m)
P total = 2940 Pa + 882 Pa
P total = 3,822 Pa
Answer:
The total gauge
pressure at the bottom is 3,822 Pa.
The answer would be the one where the left side is less than or equal to 130 because 130 has to be the greatest value and the value of the w's cannot exceed 130, but they can equal it
12kN is equal to 12000 N
and the perpendicular component will be
[email protected] mg = 12000 N
cos10°= 0.984
thus it will be 12000*0.984 = 11808N
the frictional force will be
[email protected]sin10° = 0.1736
and hence it will be = 2083N
It should be, I mean it will be more organized for them
Answer:
Its called the hydrosphere UwU!
Explanation:
