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son4ous [18]
3 years ago
11

Determine the acceleration of Earth due to its motion around the Sun. Assume the Earth's orbit to be circular with a radius of 1

.5 x 10^8 km.
Physics
1 answer:
Pie3 years ago
8 0

Answer:

Explanation:

Given

Radius of orbit r=1.5\times 10^8\ km

As earth moves around sun it experiences a centripetal force on it which is given by

a_c=\frac{v^2}{r}

where v=velocity of earth

Time period of Revolution

T=\frac{2\pi \cdot r}{v}

time period is 365 days i.e. 3.153\times 10^7\ s

v=\frac{2\pi \times 1.5\times 10^{11}}{3.153\times 10^7}

v=2.98\times 10^4\ m/s

a_c=\frac{v^2}{r}

a_c=\frac{9\times 10^8}{1.5\times 10^{11}}

a_c=0.006\ m/s^2

acceleration due to gravity is 9.8\ m/s^2

a_c is less than gravity

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