Answer: The time required for the impluse passing through each other is approximately 0.18seconds
Explanation:
Given:
Length,L = 50m
M/L = 0.020kg/m
FA = 5.7×10^2N
FB = 2.5×10^2N
The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.
Ca(t) + CB(t) = 50
Where CA and CB are the velocities of the wire A and B
t = 50/ (CA + CB)
But C = Sqrt(FL/M)
Substituting gives:
t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))
t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))
t = 50 / (168.62 + 111.83)
t = 50/280.15
t = 0.18 seconds
At the center of a 50 m diameter circular ice rink, if a 77 kg skater traveling at 2.3
m/s and then collides with a 63 kg skates traveling at 3.7 m/s. This is how
long it will take them to glide to the edge of the rink:
Speed after the collision= √{[77(2.3)77^2]
+ [63(3.7)^2]} / (77+63)=2.09 m/s
For them to be able to get to the edge
which is 50 m away it will take them 23.9
seconds.
Answer:
first one is b 2nd one is a 3rd is c and the 4th one is c also
Explanation: have a nice day
Answer:
B. holding a coffee mug
Explanation:
Something must move a distance for work to be done.
A peak = A Rms x Sq root 2
Therefore 3.6 x sq root of 2
A peak = 5.09
