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soldi70 [24.7K]
2 years ago
13

Write the formula for kinetic energy that uses force in its equation. Calculate the kinetic energy generated when a 2500 N force

is applied to a car when moving it 200 m. Show work.
Physics
1 answer:
djyliett [7]2 years ago
8 0

Answer:

500000 J

Explanation:

ΔKE =Work = F*d = 2500 N * 200 m =500000 J

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The mass of a certain neutron star is 2.5x10^30kg and the radius 7000m. what is the force of gravity on a 1kg object of the surf
Makovka662 [10]

Answer:

3.42N

Explanation:

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Use the equation: F = (GMm)/(r^2)

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G = gravitational constant (6.7x10^-11)

M = mass1 (2.5x10^30kg)

m = mass2 (1kg)

r = radius (7000m)

Plug it in: F = ((6.7x10^-11)(2.5x10^30)(1)) / (7000^2)

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3 years ago
Which of the following statements is correct A. College degree isn't as important as it was in the past b. Over time, I can earn
julia-pushkina [17]

Answer:

I'd say C is the answer they want, though my pedantic side wants to argue for B being true as well.

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3 years ago
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision.
IgorLugansk [536]

Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}

where:

m₁ = mass of the car = 1000 [kg]

v₁ = velocity of the car = 10 [m/s]

m₂ = mass of the truck = 2000 [kg]

v₂ = velocity of the truck = 0 (stationary)

v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

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7 0
3 years ago
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Rashid [163]

Answer:

KE = 0.5 * m * v², where: m - mass, v - velocity.

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