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aliya0001 [1]
3 years ago
10

Can someone please explain to me in simple terms Einsteins theory of relativity, also known as time dialation?

Physics
1 answer:
alexira [117]3 years ago
5 0

Answer:

Time dilation. Time dilation, in the theory of special relativity, the “slowing down” of a clock as determined by an observer who is in relative motion with respect to that clock.The world's most accurate clock has neatly shown how right Albert Einstein was 100 years ago, when he proposed that time is a relative concept and the higher you live above sea level the faster you should age. Einstein's theory of relativity states that time and space are not as constant as everyday life would suggest.The theory of relativity usually encompasses two interrelated theories by Albert Einstein: special relativity and general relativity. Special relativity applies to all physical phenomena in the absence of gravity. General relativity explains the law of gravitation and its relation to other forces of nature.

Explanation:

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What is the minimum tangential velocity a space station would need to simulate earth gravity if the radius is 50 meters ?
Aneli [31]

Explanation:

angular velocity is given by

w =  \sqrt{ \frac{g}{r} }

w =  \sqrt{ \frac{9.8}{25} }

w = 0.626

now tangential velocity is

V = rw

= 25 x 0.626

= 15.65 m/s

5 0
3 years ago
At a certain time a particle had a speed of 17 m/s in the positive x direction, and 3.0 s later its speed was 28 m/s in the oppo
dangina [55]

Answer:

i wanna say 11 forgive me if wrong.

Explanation:

5 0
3 years ago
A suspicious-looking man runs as fast as he can along a moving sidewalk from one end to the other, taking 2.10 s. Then security
N76 [4]

Answer:1.37

Explanation:

Given

Man run along the side walk and take 2.1 s

While walking in the opposite direction it takes 13.2 s

Let the speed of man and sidewalk be v & v_s

Let the distance between two points be x

x=(v+v_s)2.1 ------1

x=(v-v_s)13.2-----2

From 1 & 2 we can get

2.1v+2.1v_s=13.2v-13.2v_s

15.3v_s=11.1v

\frac{v}{v_s}=\frac{15.3}{11.1}=1.37

7 0
3 years ago
What forces are used to jump over a wall?
k0ka [10]

Answer:

Potential and kinetic

Explanation:

4 0
3 years ago
A 1.2 kg ball drops vertically onto a floor from a height of 32 m, and rebounds with an initial speed of 10 m/s.
iren [92.7K]

Explanation:

Given that,

Mass of the ball, m = 1.2 kg

Initial speed of the ball, u = 10 m/s

Height of the floor from ground, h = 32 m

(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 32}

v = -25.04 m/s (negative as it rebounds)

The impulse acting on the ball is equal to the change in momentum. It can be calculated as :

J=m(v-u)

J=1.2\times (-25.04-10)

J = -42.048 kg-m/s

(b) Time of contact, t = 0.02 s

Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :

J=\dfrac{F}{t}

F=J\times t

F=42.048\times 0.02

F = 0.8409 N

Hence, this is the required solution.

5 0
3 years ago
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