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Crank
3 years ago
5

I need help on this

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0

Answer:

See below

Step-by-step explanation:

Which is the closest to 6

\sqrt{34}

\sqrt{39\\

\sqrt{35

or \sqrt{38}

So, find the square root of each ( I suggest using a calculator)

\sqrt{34} = 5.83\\\sqrt{39} = 6.24\\\sqrt{35} = 5.91 \\\sqrt{38} = 6.16

Which is closest? Let's see.

6 - 5.83 = 0.17

6.24 - 6 = 0.24

6 - 5.91 = 0.09

6.16 - 6 = 0.16

Find the smallest #

0.09 is the smallest, so 5.91 is the closest. Square the #, we get \sqrt{35}

Hope this helps! =D

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What is the slope intercept of the equation of the line through the given point (0,3) and (-4,-1)
cestrela7 [59]

Answer:

y=x+3

Step-by-step explanation:

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8 0
3 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

7 0
3 years ago
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