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2 years ago

I need help on this

Mathematics

1 answer:

Viefleur [7K]2 years ago

4 0

Answer:

See below

Step-by-step explanation:

Which is the closest to 6

$\sqrt{34}$

$\sqrt{39\\$

$\sqrt{35$

or $\sqrt{38}$

So, find the square root of each ( I suggest using a calculator)

$\sqrt{34} = 5.83\\\sqrt{39} = 6.24\\\sqrt{35} = 5.91 \\\sqrt{38} = 6.16$

Which is closest? Let's see.

6 - 5.83 = 0.17

6.24 - 6 = 0.24

6 - 5.91 = 0.09

6.16 - 6 = 0.16

Find the smallest #

0.09 is the smallest, so 5.91 is the closest. Square the #, we get $\sqrt{35}$

Hope this helps! =D

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anyanavicka [17]

we know that

If two lines are parallel , then their slopes are the same

we will proceed to calculate the slope of each line to determine the solution.

The formula to calculate the slope m between two points of the line is equal to

$m=\frac{(y2-y1)}{(x2-x1)}$

case N 1) line AB

Let

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substitute the values

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vase N 2) line FG

Let

$F(-3,-1)\\G(3,-3)$

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$m=\frac{(-2)}{(6)}$

$m=-1/3$

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therefore

The line EG is not the solution

case N 3) line CD

Let

$C(-3,0)\\D(3,2)$

substitute the values

$m=\frac{(2-0)}{(3+3)}$

$m=\frac{(2)}{(6)}$

$m=1/3$

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therefore

The line CD is not the solution

case N 4) line HJ

Let

$H(-1,-4)\\J(1,2)$

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therefore

the answer is the option

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2 years ago

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Free_Kalibri [48]

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