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4 years ago

What keeps an ionic bond held together?

1 answer:

4 0

In Ionic bonds one atom is positively charged and the other atom is negatively charged, therefore, it is the opposite charge of the ions that attracts them to one another and holds them together.

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A student drops a rubber ball onto a surface. Assume that this is a closed system. The ball bounces, but each successive bounce

spayn [35]

I would say D.) The ball bounces many times suggesting the energy is used up efficiently

5 0

2 years ago

Read 2 more answers

Which circle passes through more continents antarctic or arctic

Alex787 [66]

Answer:Arctic circle

Explanation:

Arctic circle is one of the circles of latitude. It is located at the northern region if the equator and passes through more than one continent. These continent includes: North Asia,

Northern America, and

Europe.

In these continent, it passes through eight known counties. These countries includes: Canada, Russia, Norway, Sweden, Finland, Denmark, Alaska and Iceland. It covers 4% of the Earth surface and it's climatic conditions are extreme.

5 0

4 years ago

Can you please answer this question?

Sidana [21]

I think its b too but i may be wrong

5 0

4 years ago

he drag characteristics of a torpedo are to be studied in a water tunnel using a 1 : 7 scale model. The tunnel operates with fre

dusya [7]

Answer:20.03 m/s

Explanation:

Given

$L_r=1:7$

velocity of Prototype $v_p=53 m/s$

Taking Froude number same for both flow as it is a dimensionless number for different flow regimes in open Flow

$(\frac{v_m}{\sqrt{L_mg}})=(\frac{v_p}{\sqrt{L_pg}})$

$v_m=v_p\times \sqrt{\frac{L_m}{L_p}}$

$v_m=53\times \frac{1}{\sqrt{7}}$

$v_m=20.03 m/s$

4 0

3 years ago

A bullet with mass 0.04000 kg, traveling at a speed of 310.0 m/s, strikes a stationary block of wood having mass 6.960 kg. The b

ch4aika [34]

Answer:

1.77 m/s

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............................ Equation 1

Where m = mass of the bullet, m' = mass of the block, u = initial velocity of the bullet, u' = initial velocity of the block, V = Velocity of the bullet-wood combination immediately after collision

make V the subject of the equation

V = (mu+m'u')/(m+m').................. Equation 2

Given: m = 0.04 kg, m' = 6.96 kg, u = 310 m/s, u' = 0 m/s (stationary)

Substitute into equation 2

V = (0.04×310+6.96×0)/(0.04+6.96)

V = 12.4/7

V = 1.77 m/s

Hence the speed, in m/s, of the bullet-plus-wood combination immediately after the collision is 1.77 m/s

6 0

4 years ago