Answer:
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Explanation:
Answer:
100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.
Explanation:
Heat = mass * lf
Latent heat of fusion (lf) of water is 334J/g
Heat = 300g * 334 J/g
Heat = 100,200J of heat
<span>A design is remodeled after analysis and tested again.</span>
Explanation:
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<h3>Solution for the above question : -</h3>
Ohm's law states that :
the terms used are :
let's solve for electric current :
