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Lostsunrise [7]
4 years ago
5

What keeps an ionic bond held together?

Physics
1 answer:
BlackZzzverrR [31]4 years ago
4 0
In Ionic bonds one atom is positively charged and the other atom is negatively charged, therefore, it is the opposite charge of the ions that attracts them to one another and holds them together.
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*Brainliest if answered with in 5 min*
levacccp [35]

Your answer is going to be 0 degrees Kelvin!

8 0
3 years ago
Read 2 more answers
Is a body which is moving in a negative direction but has a positive acceleration speeding up or slowing down?​
melamori03 [73]

Answer:

An object with negative acceleration could be speeding up, and an object with positive acceleration could be slowing down.

Explanation:

hope this helps

have a great day/night

7 0
3 years ago
a cement block accidentally falls from rest from the ledge of a 80.6-m-high building. When the block is 10.8 m above the ground,
fomenos

Answer:

0.229 seconds

Explanation:

Given:

y₀ = 80.6 m

v₀ = 0 m/s

a = -9.8 m/s²

We need to find the difference in times when y = 10.8 m and y = 2.10 m.

When y = 10.8 m:

y = y₀ + v₀ t + ½ at²

10.8 = 80.6 + (0) t + ½ (-9.8) t²

10.8 = 80.6 − 4.9 t²

4.9 t² = 69.8

t = 3.774

When y = 2.10 m:

y = y₀ + v₀ t + ½ at²

2.10 = 80.6 + (0) t + ½ (-9.8) t²

2.10 = 80.6 − 4.9 t²

4.9 t² = 78.5

t = 4.003

The difference is:

4.003 − 3.774 = 0.229

The man has 0.229 seconds to get out of the way.

5 0
4 years ago
Las carreras de velocidad pura en el atletismo son:
zheka24 [161]
La respuesta es la letra b
8 0
3 years ago
A 0.05-m3 rigid tank initially contains refrigerant-134a at 0.8 MPa and 100 percent quality. The tank is connected by a valve to
lesya692 [45]

Answer:

A= 203 KJ

B= 54 Kg

Explanation:

The initial specific volumes and internal energies are obtained from A-12 for a given pressure and state. The enthalpy of the refrigerant in the supply line is determined using the saturated liquid approximation for the given temperature with data from A-11. The mass that has entered the tank is:

Δm = m₂ – m₁

= V(1/α₂ – 1/α₁)

= 0.05 (1/0.0008935 – 1/ 0.025645)Kg

= 54Kg

The heat transfer is obtained from the energy balance:

ΔU= m_i_n h_i_n+  Q_n_e_t

m₂u₂ – m₁u₂ = m_i_nh_i_n + Q_n_e_t

Q_n_e_t= m₂u₂ – m₁u₁ – m_i_n

= V/α₂u₂ - V/α₁u₁ – m_i_n

=(0.05/0.0008935 . 116.72 – 0.05/0.025645 . 246.82 – 54.108.28) Kj

= 203 KJ

8 0
3 years ago
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