Answer:
41.4 s
Explanation:
Given data
- Rate constant (k): 8.42 × 10⁻² s⁻¹ at 800 °C
- Initial concentration of A ([A]₀): 5.00 M
- Concentration of A at a time t ([A]): 0.153 M
Let's consider the following reaction of first order with respect to A.
2 A ⇒ B
We can find the time that it will take for A to decrease from 5.00 M to 0.153 M using the following expression.
![ln([A]/[A]_0)=-k.t\\ln(0.153M/5.00M)=-8.42 \times 10^{-2}s^{-1} .t\\t = 41.4 s](https://tex.z-dn.net/?f=ln%28%5BA%5D%2F%5BA%5D_0%29%3D-k.t%5C%5Cln%280.153M%2F5.00M%29%3D-8.42%20%5Ctimes%2010%5E%7B-2%7Ds%5E%7B-1%7D%20%20%20.t%5C%5Ct%20%3D%2041.4%20s)
An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal. A covalent bond involves a pair of electrons being shared between atoms.
Explanation:
It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.
And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.
= 0.0625 L/hr
As, molar mass of He is 4 g/mol and molar mass of 
is 32 g/ mol.
Now,
= 2.83
or, rate of 
= 
Rate of = 0.022 L/hr.
This means that 0.022 L of gas effuses in 1 hr
So, time taken for the effusion of 1.5 L of gas is calculated as follows.
= 68.18 hour
Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.
Answer:
6 carbon dioxide molecules
Explanation:
The Calvin cycle generates the necessary reactions for the fixation of carbon in a solid structure for the formation of glucose and, in turn, regenerates the molecules for the continuation of the cycle.
The Calvin cycle is also known as the dark phase of photosynthesis or also called the carbon fixation phase. It is known as the dark phase because it is not light dependent as is the first phase or light phase
.
This second stage of photosynthesis fixes the carbon of the absorbed carbon dioxide and generates the precise number of biochemical elements and processes necessary to produce sugar and recycle the remaining material for continuous production.
The Calvin cycle uses the energy produced in the light phase of photosynthesis to fix the carbon dioxide (CO2) carbon in a solid structure such as glucose, in order to generate energy.
The glucose molecule composed of a six-carbon main structure will be further processed in glycolysis for the preparatory phase of the Krebs cycle, both part of the cellular respiration.
The Calvin cycle produces in six turns a six-carbon glucose molecule and regenerates three RuBP that will be catalyzed again by the RuBisCo enzyme with CO2 molecules for the restart of the Calvin cycle.
The Calvin cycle requires six molecules of CO2, 18 ATP and 12 NADPH produced in the light phase of photosynthesis to produce a glucose molecule and regenerate three RuBP molecules.
