Answer:
b) Document lessons learned.
Explanation:
First he should do documentation
then C
then D
then A
<em>Your answer is:</em>
<em>c) </em><u><em>20°</em></u>
<em />
<em>∝ </em><em>Sidhdi</em>
Set up a free body diagram.
<span>and by reason, Tcd = Tbd </span>
<span>Tbd y = 275 - 300*sinθ </span>
<span>Tcd y = Tc - 300*sin30 </span>
<span>Tbd x = 300*cosθ </span>
<span>Tcdx = 300 * cos30 </span>
<span>Tbd^2 = (275 - 300*sinθ)^2 + (300*cosθ)^2 </span>
<span>Tcd^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>(275 - 300*sinθ)^2 + (300*cosθ)^2 = (300*sin30)^2 + (300 * cos30)^2 </span>
<span>etc.</span>
Answer:
1.5 × 
J
Explanation:
The initial force, which in this case is the external force is equal to 15N. Logically, when 150 Joules of work is done upon that system the overall energy will increase by that very same amount of work applied on the system which is 150 J.
Answer:
37.8225 J
Explanation:
kinetic energy = 1/2 of mass x 
