Answer:
- A vibrating object
- a medium to travel
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Answer:
increase
Explanation:
As acceleration is the time rate of change of velocity
a = Δv/t
with t in the denominator, smaller time values result in greater acceleration values with constant velocity change.
Answer:2 m right
Explanation:
Given
First child is sitting 1 m left from Pivot point
Mass of second child is half of first
Let mass of first child be m
Second child 
In order to balance see saw torque must be zero about pivot

x=2 m right from pivot point
Answer
given,
vertical speed of stone,v = 12 m/s
height of the cliff = 70 m
a) time taken by the stone to reach at the bottom of the cliff
We know that,
S = u t + 1/2 a t²
- 70 = 12 t - 0.5 x 9.8 t²
4.9 t² - 12 t - 70 = 0
solving the equation
t = 5.2 s (neglecting the negative value)
b) again using equation of motion
v = u + a t
v = 12 - 9.8 x 5.2
v = -38.96 m/s
ignoring the negative sign
magnitude of velocity is equal to 38.96 m/s
c) total distance travel by the stone
vertical distance covered by the stone
v² = u² + 2 g h
0 = 12² - 2 x 9.8 x h
h = 7.34 m
to reach the stone to the same level distance travel be doubled.
Total distance travel by the stone
H = h + h + 70
H = 7.34 x 2 + 70
H = 84.7 m.
Explanation:
It is given that,
The distance from the pitcher's mound to the batter is 43 feet, d = 43 feet = 0.00814 miles
Speed with which ball leaves the ball, v = 110 mph
Let t is the time elapses between the hit and the ball reaching the pitcher. It is given by :


t = 0.000074 hours
or
t = 0.2664 seconds
So, the time between the hit and the ball reaching the pitcher is 0.2664 seconds. Hence, this is the required solution.