Answer:

Explanation:
This is a uniformly accelerated motion, so we can determine the deceleration of the car by using a suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the car in this problem,
u = 27.8 m/s
v = 0
s = 17 m
Solving for a, we find the acceleration:

The concept required to solve this problem is related to the wavelength.
The wavelength can be defined as the distance between two positive crests of a wave.
The waves are in phase, then the first distance is

And out of the phase when

Thus the wavelength is

Here,
Wavelength
If we rearrange the equation to find it, we will have



Therefore the wavelength of the sound is 20cm.
Answer:
E_Phase = 560V
Explanation:
The computation of the voltage i.e. dropped across each phase is shown below:
Given that
The delta connection line voltage is
E_line = 560 V
And, in the case of delta connection, the line voltage would be equivalent to the phase voltage
That means
E_Phase = E_Line
= 560 V
Hence, the voltage i.e. dropped across each phase is
E_Phase = 560V
The correct answer would be yes