Matter. I don't really know how to explain it. Sorry. But anyways, Hope this helps!
Thermal conductions
K= QL/ART
Aluminium T₁ = 10 + 273.15
T₂ = 283.15k
205 = 2.0 × 0.30/4× 10⁻⁴ × (T₂ - 283.15)
Copper
385 = Q × 0.70/4×10⁻⁴ ×(433.15 - T₂)
Where T₃ = 160 + 273.15
T₃ = 433.15K
From 2 to 3
205/385 = 0.30/0.70 × 433.15 - T₂/T₂ - 283.15
= 0.53T₂ -150.06 = 181.92 - 0.42 T₂
→ 0.95T₂ = 331.98 ⇒ T₂ = ₂349.45k
T₂ = 76.3°c
=77°c.
Answer:
Species distribution
Explanation:
Species dispersion patterns—or distribution patterns—refer to how the individuals in a population are distributed in space at a given time. The individual organisms that make up a population can be more or less equally spaced.
Answer:
706.68 N
Explanation:
By Hooke's law,
Using the values in the question,
When e = 0.4 m,
