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3 years ago

How have earthquake data been used to explore the size of convection currents in the mantle?

1 answer:

8 0

<span>Vibration waves from earth quakes travel through the earth and have measurable speed. And the different temperatures and fluidity of the various regions of the mantle will change that speed and or reflect the vibration waves in different directions. With multiple vibration sensors around the world the time that it takes for vibrations to travel from one part of the world to another will tell you what is inside.</span>

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In groupthink, the decision is less important than

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Decision is less important than taking in part of discussions.

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3 years ago

A good daily schedule should include

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It should tasks that you must do in order for it to be a good schedule.

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Read 2 more answers

A 57 kg skier starts from rest at a height of H = 27 m above the end of the ski-jump ramp. As the skier leaves the ramp, his vel

Hatshy [7]

Answer:

(a) $h=5.95m$

(b) h is the same

Explanation:

According to the law of conservation of energy:

$E_i=E_f\\U_i+K_i=U_f+K_f$

The skier starts from rest, so $K_i=0$ and we choose the zero point of potential energy in the end of the ramp, so $U_f=0$ . We calculate the final speed, that is, the speed when the skier leaves the ramp:

$mgH=\frac{mv^2}{2}\\v=\sqrt{2gH}\\v=\sqrt{2(9.8\frac{m}{s^2})(27m)}\\v=23\frac{m}{s}$

Finally, we calculate the maximum height h above the end of the ramp:

$v_f^2=v_i^2-2gh\\$

The initial vertical speed is given by:

$v_i=vsin\theta$

and the final speed is zero, solving for h:

$h=\frac{v_i^2}{2g}\\h=\frac{((23\frac{m}{s})sin(28^\circ))^2}{2(9.8\frac{m}{s^2})}\\h=5.95m$

(b) We can observe that the height reached does not depend on the mass of the skier

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4 years ago

Four students measured the acceleration of gravity. The accepted value for

Ratling [72]

Answer: The student with the largest measurement of percentage error is student 4. Option A is correct.The percent error shows the disparity between the observed value and the actual value. It is given by the expression.

Therefore, we can conclude that the student's measurement that has the largest percent error is student 4.

Explanation:

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2 years ago

A bullet of mass 20g is a fired with a velocity of 50mls from a gun of mass 2.5kg. Calculate the recoil velocity of the gun.

jok3333 [9.3K]

Answer:

v = - 0.4 m/s

Explanation:

Initial momentum is zero as neither gun nor bullet have velocity

Conservation of momentum

0 = 0.020(50) + 2.5v

v = - 0.4 m/s

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3 years ago