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exis [7]
3 years ago
9

Resonance can be used to___ sound

Physics
2 answers:
nika2105 [10]3 years ago
7 0
Hear in a way that's the answer
Arturiano [62]3 years ago
4 0
The answer is amplify.
Please mark me as brainliest. Thanks!!
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I'm not sure but I think it's 4.5 v

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The type of waves that transmit cell phone messages are most likely
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Cell phones use RF waves from nearby cell towers. RF waves fall in between FM radio waves and microwaves
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The science of classifying and naming organisms based on their different characteristics is called ______________.
Fofino [41]

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Biology

Explanation:

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A racquet ball with mass m = 0.256 kg is moving toward the wall at v = 11.8 m/s and at an angle of θ = 29° with respect to the h
icang [17]

Answer:

Part a)

P = 5.72 kg m/s

Part b)

\Delta P = 2.93 kg m/s

Part c)

F = 44.4 N

Part d)

\Delta P = 5.02 kg m/s

Part e)

\Delta t = 0.113 s

Part f)

\Delta K = 0

Explanation:

As we know that initial velocity of the ball is given as

v = 11.8 cos29 \hat i + 11.8 sin29 \hat j

v_i = 10.3 \hat i + 5.72 \hat j

Now final velocity of the system is given as

v_f = 10.3\hat i - 5.72\hat j

Part a)

now magnitude of initial momentum is given as

P = mv

P = 0.256(11.8)

P = 5.72 kg m/s

Part b)

Change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(5.72 + 5.72)

\Delta P = 2.93 kg m/s

Part c)

As we know that average force is defined as the rate of change in momentum

so here we have

F = \frac{\Delta P}{\Delta t}

F = \frac{2.93}{0.066}

F = 44.4 N

Part d)

Magnitude of change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.256(7.8 + 11.8)

\Delta P = 5.02 kg m/s

Part e)

As we know that in 2nd case the force is same as the initial force

so we will have

\frac{\Delta P}{\Delta t} = F

\frac{5.02}{\Delta t} = 44.4

\Delta t = 0.113 s

Part f)

Since this is elastic collision so change in kinetic energy must be ZERO

\Delta K = 0

8 0
3 years ago
A child in danger of drowning in a river is being carried down-stream by a current that flows uniformly with a speed of 2.20 m/s
zmey [24]

Answer:

The angle is 65.6°.

Explanation:

Given that,

Speed = 2.20 m/s

Distance from the shore= 500 m

Distance from the bottom= 1100 m

Speed of boat = 7.30 m/s

According to figure,

We need to calculate the angle with shore

Using formula of angle

\tan\theta=\dfrac{y}{x}

Put the value into the formula

\tan\theta=\dfrac{500}{1100}

\theta=\tan^{-1}(\dfrac{500}{1100})

\theta=24.4^{\circ}

We need to calculate the angle

\alpha=90-\theta

Put the value into the formula

\alpha=90-24.4

\alpha=65.6^{\circ}

Hence, The angle is 65.6°.

5 0
3 years ago
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