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3 years ago

Which statement is true about the particles of a solid, when a solid changes into a liquid

Chemistry

1 answer:

erica [24]3 years ago

5 0

Answer:

Which statement is true about the particles of a solid when the solid changes into a liquid? (5 points)

a. They stop vibrating.

Selected: b. Their kinetic energy increases. This answer is correct.

c. They move closer to each other.

d. The attractive force between them increases.

Explanation: when a solid turns to a liquid it means it was melted and it needs to be heated to melt meaning the kinetic energy increases because the solid was heated up. Also this was on my test and i got it right so yeah.

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Write the ground state electron configuration of zn using the noble-gas shorthand notation.

V125BC [204]

Atomic Number of Zinc is 30, means it contains 30 electrons. So, its electronic configuration is as follow,

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰
As,
1s², 2s², 2p⁶, 3s², 3p⁶ = Argon
So,
Electronic configuration of Zinc in shorthand notation is as follow,

[Ar] 4s², 3d¹⁰

8 0

3 years ago

HELLLLPPPPPPP

Misha Larkins [42]

C. polymerization....

4 0

3 years ago

An old antacid commercial claimed that each tablet of their product could neutralize 47 times its mass in stomach acid. The acti

butalik [34]

Answer : The number of moles of HCl neutralize is, 0.00824 moles.

Explanation :

The given balanced chemical reaction is:

$NaAl(OH)_2CO_3+4HCl\rightarrow NaCl+AlCl_3+3H_2O+CO_2$

First we have to calculate the moles of $NaAl(OH)_2CO_3$

$\text{Moles of }NaAl(OH)_2CO_3=\frac{\text{Mass of }NaAl(OH)_2CO_3}{\text{Molar mass of }NaAl(OH)_2CO_3}$

Molar mass of $NaAl(OH)_2CO_3$ = 144 g/mol

$\text{Moles of }NaAl(OH)_2CO_3=\frac{0.296g}{144g/mol}=0.00206mol$

Now we have to calculate the moles of HCl.

From the balanced chemical reaction we conclude that,

As, 1 mole of $NaAl(OH)_2CO_3$ react with 4 moles of HCl

So, 0.00206 mole of $NaAl(OH)_2CO_3$ react with $0.00206\times 4=0.00824$ moles of HCl

Thus, the number of moles of HCl neutralize is, 0.00824 moles.

8 0

3 years ago

The activation energy for the isomerization ol cyclopropane to propene is 274 kJ/mol. By what factor does the rate of this react

Bond [772]

Answer:

The rate of the reaction increased by a factor of 1012.32

Explanation:

Applying Arrhenius equation

ln(k₂/k₁) = Ea/R(1/T₁ - 1/T₂)

where;

k₂/k₁ is the ratio of the rates which is the factor

Ea is the activation energy = 274 kJ/mol.

T₁ is the initial temperature = 231⁰C = 504 k

T₂ is the final temperature = 293⁰C = 566 k

R is gas constant = 8.314 J/Kmol

Substituting this values into the equation above;

ln(k₂/k₁) = 274000/8.314(1/504 - 1/566)

ln(k₂/k₁) = 32956.4589 (0.00198-0.00177)

ln(k₂/k₁) = 6.92

k₂/k₁ = exp(6.92)

k₂/k₁ = 1012.32

The rate of the reaction increased by 1012.32

3 0

4 years ago

Read 2 more answers

Give the chemical symbol of an element in the third period (row) of the periodic table with four 3p electrons.

Ann [662]

<u>Answer: </u>The chemical symbol of the element is Sulfur.

<u>Explanation:</u>

The element which is present in third period of the periodic table having four 3p electrons is Sulfur. Sulfur is the 16th element of the periodic table which has 6 valance electrons.

The electronic configuration of this element is: $[Ne]3s^23p^4$

This element is considered as a non-metal because it will accept electrons in order to attain stable electronic configuration.

Hence, the chemical symbol of the element is Sulfur.

7 0

3 years ago