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vazorg [7]
3 years ago
11

How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

Chemistry
2 answers:
dusya [7]3 years ago
6 0

Answer:

1.3 moles/ 1.33150727 moles

Explanation:

350g x 1 mol/262.86g = 1.3 moles

jok3333 [9.3K]3 years ago
6 0

The molar mass of Mg3(PO4)2 is 262.855 g/mol

Atomic weight of the parts:

Mg 24.3050   x 3 = 72.92

P 30.973762   x2 = 61.95

O 15.9994   x8 = 127.995

There are 262.855 grams in one mole, so  

350.00 g x (262.855g/1 mole) = 1.33 moles Mg3(PO4)2

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Explanation:

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Looking at the gases listed, C2H6 have the highest average kinetic energy at this temperature since it has the lowest molecular mass. This reasoning is directly derived from Graham's law of diffusion in gases.

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3 years ago
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Answer:

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3 years ago
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