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3 years ago

How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

Chemistry

2 answers:

dusya [7]3 years ago

6 0

Answer:

1.3 moles/ 1.33150727 moles

Explanation:

350g x 1 mol/262.86g = 1.3 moles

jok3333 [9.3K]3 years ago

6 0

The molar mass of Mg3(PO4)2 is 262.855 g/mol

Atomic weight of the parts:

Mg 24.3050 x 3 = 72.92

P 30.973762 x2 = 61.95

O 15.9994 x8 = 127.995

There are 262.855 grams in one mole, so

350.00 g x (262.855g/1 mole) = 1.33 moles Mg3(PO4)2

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Determine the number of moles of the compound and determine the number of each type of atom in each of

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Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles.

For A: 2.12 g of potassium bromide

Given mass of KBr = 2.12 g

Molar mass of KBr = 119 g/mol

Putting values in equation 1, we get:

$\text{Moles of KBr}=\frac{2.12g}{119g/mol}=0.0178mol$

1 mole of potassium bromide contains 1 mole of potassium element and 1 mole of bromide element.

So, 0.0178 moles of potassium bromide will contain $(1\times 0.0178\times 6.022\times 10^{23})=1.07\times 10^{22}$ number of potassium atoms and

For B: 0.1488 g of phosphoric acid

Given mass of phosphoric acid = 0.1488 g

Molar mass of phosphoric acid = 98 g/mol

Putting values in equation 1, we get:

$\text{Moles of phosphoric acid}=\frac{0.1488g}{98g/mol}=0.00152mol$

1 mole of phosphoric acid contains 3 moles of hydrogen element, 1 mole of phosphorus element and 4 moles of oxygen element.

So, 0.00152 moles of phosphoric acid will contain $(3\times 0.00152\times 6.022\times 10^{23})=2.75\times 10^{21}$ number of hydrogen atoms, $(1\times 0.00152\times 6.022\times 10^{23})=9.15\times 10^{20}$ of phosphorus atoms and $(4\times 0.00152\times 6.022\times 10^{23})=3.66\times 10^{21}$ number of oxygen atoms.

For C: 23 kg of calcium carbonate

Given mass of calcium carbonate = 23 kg = 23000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of calcium carbonate = 100 g/mol

Putting values in equation 1, we get:

$\text{Moles of calcium carbonate}=\frac{23000g}{100g/mol}=230mol$

1 mole of calcium carbonate contains 1 mole of calcium element, 1 mole of carbon element and 3 moles of oxygen element.

So, 230 moles of calcium carbonate will contain $(1\times 230\times 6.022\times 10^{23})=1.38\times 10^{26}$ number of calcium atoms,

For D: 78.452 g of aluminium sulfate

Given mass of aluminium sulfate = 78.452 g

Molar mass of aluminium sulfate = 342.15 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium sulfate}=\frac{78.452g}{342.15g/mol}=0.229mol$

1 mole of aluminium sulfate contains 2 moles of aluminium element, 3 moles of sulfur element and 12 moles of oxygen element.

So, 0.229 moles of aluminium sulfate will contain $(2\times 0.229\times 6.022\times 10^{23})=2.76\times 10^{23}$ number of aluminium atoms, $(3\times 0.229\times 6.022\times 10^{23})=4.14\times 10^{23}$ of sulfur atoms and $(12\times 0.229\times 6.022\times 10^{23})=1.65\times 10^{24}$ number of oxygen atoms.

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Given mass of caffeine = 0.1250 mg = $0.125\times 10^{-3}$ g (Conversion factor: 1 g = 1000 mg)

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$\text{Moles of caffeine}=\frac{0.125\times 10^{-3}g}{194.2g/mol}=6.44\times 10^{-7}mol$

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