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vazorg [7]
3 years ago
11

How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

Chemistry
2 answers:
dusya [7]3 years ago
6 0

Answer:

1.3 moles/ 1.33150727 moles

Explanation:

350g x 1 mol/262.86g = 1.3 moles

jok3333 [9.3K]3 years ago
6 0

The molar mass of Mg3(PO4)2 is 262.855 g/mol

Atomic weight of the parts:

Mg 24.3050   x 3 = 72.92

P 30.973762   x2 = 61.95

O 15.9994   x8 = 127.995

There are 262.855 grams in one mole, so  

350.00 g x (262.855g/1 mole) = 1.33 moles Mg3(PO4)2

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azamat

Answer:

You can view more details on each measurement unit: molecular weight of Copper(I) Oxide or grams The molecular formula for Copper(I) Oxide is Cu2O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Copper(I) Oxide, or 143.0914 grams.

Explanation:

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3 years ago
Name the following alkyne: CH3CH₂C = CCH₂CH₂CH3
liubo4ka [24]

The given alkyne is Option A 3-heptyne

<h3>What is an Alkyne ?</h3>

The hydrocarbon having at least one C-C triple bond is called an Alkyne.

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In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.

It has been asked in the question that

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brainly.com/question/23508203

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6 0
2 years ago
Tin reacts with Fluorine to form two different compounds, A and B. Compounds A contains 77.0 g tin for each 24.6 g of fluorine.
Ratling [72]
A contains 38.5 g of tin for each 12.3 g of fluorine: 
<span>mole ratio: </span>
<span>(38.5 g)/(118.71 g/mol):(12.3 g)/(18.998 g/mol) = 0.324:0.647 = 1:2 ⇒ SnF₂ </span>

<span>B contains 56.5 g of tin for each 36.2 g of fluorine: </span>
<span>mole ratio: </span>
<span>(56.5 g)/(118.71 g/mol):(36.2 g)/(18.998 g/mol) = 0.476:1.905 = 1:4 ⇒ SnF₄

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.


</span>
3 0
3 years ago
Read 2 more answers
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the vector is an arrow that shows both <em><u>speed</u></em> and direction of an object

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