An Ohm or a electrical resistance is a measure of the amount of electrical energy transferred by an electric charge as it moves from one point to another circuit. The voltage between two points in a circuit can be measured with a voltmeter.
The gravity ( im not sure)
A)<span>
dQ = ρ(r) * A * dr = ρ0(1 - r/R) (4πr²)dr = 4π * ρ0(r² -
r³/R) dr
which when integrated from 0 to r is
total charge = 4π * ρ0 (r³/3 + r^4/(4R))
and when r = R our total charge is
total charge = 4π*ρ0(R³/3 + R³/4) = 4π*ρ0*R³/12 = π*ρ0*R³ / 3
and after substituting ρ0 = 3Q / πR³ we have
total charge = Q ◄
B) E = kQ/d²
since the distribution is symmetric spherically
C) dE = k*dq/r² = k*4π*ρ0(r² - r³/R)dr / r² = k*4π*ρ0(1 -
r/R)dr
so
E(r) = k*4π*ρ0*(r - r²/(2R)) from zero to r is
and after substituting for ρ0 is
E(r) = k*4π*3Q(r - r²/(2R)) / πR³ = 12kQ(r/R³ - r²/(2R^4))
which could be expressed other ways.
D) dE/dr = 0 = 12kQ(1/R³ - r/R^4) means that
r = R for a min/max (and we know it's a max since r = 0 is a
min).
<span>E) E = 12kQ(R/R³ - R²/(2R^4)) = 12kQ / 2R² = 6kQ / R² </span></span>
as per the question charlie runs to the store which is 4 km away
hence the total distance covered [S] is 4 km
he takes 30 minutes to reach the store.
hence the total time taken [t] = 30 minutes=0.5 hour
We have to calculate the average speed.
the average speed[v]=
=
=8 km/hour
then we have to calculate the total distance traveled by charlie in 1 hour.
the distance covered S=
=8 km/hour ×1 hour
=8 km
Hence the average speed of charlie is 8 km/hour and he covers a distance of 8 km in 1 hour.
Ask Barry Allen he’s the faster man alive