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Cloud [144]
3 years ago
13

A 2-Newton upward net force is being applied to a 10-kg object. What is the magnitude of the upward

Physics
1 answer:
Colt1911 [192]3 years ago
7 0
Acceleration in m/s^2 = 2/10 = 0.2 m/s^2
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Bobby places a 4.75 cm tall light bulb a distance of 33.2 cm from a concave mirror. If the mirror has a focal length of 28.2, th
Fittoniya [83]
The image distance can be determined using the mirror equation: 1/f = 1/d_o + 1/d_i, where, f is the focal length, d_o is the object distance, and d_i is the image distance. Given that f = 28.2 and d_o = 33.2 cm, the value of d_i is calculated to be 187.248 cm. On the other hand, the image height is obtained using the magnification equation wherein, h_i/h_o = -d_i/d_o, where h_i is the image height and h_o is the object height. Using the given values, h_i is equal to -26.79 cm. Note that the negative sign indicates that the image is inverted. 
3 0
3 years ago
Read 2 more answers
Convert 123,453 to a scientific notation
Natalija [7]

Answer:

1.23453*10^5 is scientific way

3 0
2 years ago
How many times did thomas edison fail before inventing the lightbulb
Rom4ik [11]

Answer:

he failed thousands of times

Explanation:

There is no known number for his failings. Edison may have failed in many of his experiments and in his schooling, but he had something better working in his favor. He had great determination and persistence.

He failed thousands of times in an attempt to develop an electric light, the great Edison simply viewed each unsuccessful experiment as the elimination of a solution that wouldn’t work, thereby moving him that much closer to a successful solution.

4 0
2 years ago
1. Which has more momentum: a bowling ball with a velocity of 7.0 m/s or a basketball with a
Andrews [41]

Answer:

kenitec energy

Explanation:

because kinetic and mass have same

3 0
3 years ago
An object travels along a straight line across a horizontal surface, and its motion is described by the velocity versus time gra
Mkey [24]

Answer:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

Explanation:

The graph seems to be missing, however we can still answer the question.

In fact, we have to keep in mind the following facts:

- In a velocity-time graph, the area under the curve represents the displacement of the object, while the slope of the curve corresponds to its acceleration.

From this, we can already say that the following option:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

is correct, while the statement

A.)Finding the slope of the line between 0 s to 5 s

is wrong.

Moreover, the average speed of an object in motion is given by

v=\frac{d}{t}

where d is the total distance covered while t is the total time taken. Once we have calculated the average speed, the total displacement over a certain time period can be simply calculated by multiplying the average speed by the time interval: so, the option

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

is also correct.

The last option remained:

B.)Dividing the change in velocity between 0 s to 5 s by the change in time

is wrong, because in this way we are calculating the acceleration, not the displacement.

6 0
3 years ago
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