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Tresset [83]
3 years ago
12

Which object would have a LARGER gravitational force acting upon it? (assume the objects are at the same height above the Earth.

)
Physics
2 answers:
Solnce55 [7]3 years ago
8 0

Newtons Second law

Force = mass x acceleration

Weight = mass x g

  • weight : the force that earth applies on an object
  • mass : the mass of the object
  • g : gravitational acceleration. Almost constant, around 9.81m/s^2 at the sea level. constant for given heights.

Given the above, the <u>more massive the object is, the larger the force acting upon it. </u>

THAT DOES NOT MEAN THAT IT'l FALL FASTER since they both have the same acceleration (g). Just larger force to the larger mass.

djverab [1.8K]3 years ago
7 0
A) 5 kg block of wood
B) 100 kg person
C) 412 kg motorcycle
D) 2540 kg elephant
Answer: D
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Artyom0805 [142]

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3 years ago
Now find the electromotive force E2(t) induced across the entirety of solenoid 2 by the change in current in solenoid 1. Remembe
lions [1.4K]

Answer:

E_{2} (t) = -\pi\mu_o} \rho^{2} n_{1}n_{2}L\frac{d }{dt}I_{1}(t)

Explanation:

Consider two solenoids that are wound on a common cylinder as shown in fig. 1. Let the cylinder have radius 'ρ' and length 'L' .

No. of turns of solenoid 1 = n₁

No. of turns of solenoid 1 = n₂

Assume that length of  solenoid is much longer than its radius, so that its field can be determined from Ampère's law throughout its entire length:

\oint \overrightarrow {B}\overrightarrow {(r)}.\overrightarrow {dl}= \mu_{o}I

We will consider the field that arises from solenoid 1, having n₁  turns per unit length. The magnetic field due to solenoid 1 passes through solenoid 2, which has n₂ turns per unit length.

Any change in magnetic flux from the field generated by solenoid 1 induces an EMF in solenoid 2 through Faraday's law of induction:

\oint \overrightarrow {B}\overrightarrow {(r)}.\overrightarrow {dl}= -\frac{d}{dt} \phi _{M}(t)

Consider B₁(t) magnetic feild generated in solenoid 1 due to current I₁(t)

Using:

                                  B_{1}(t) =\mu _{o} nI(t)\\ --- (2)

                           

Flux generated due to magnetic field B₁

                      \phi _{1}(t) = \oint \overrightarrow {B_{1}}.dA\\ ---(3)

area of solenoid = A = \pi \rho^{2}

substituting (2) in (3)

                       \phi _{1}(t) = \mu_{o} \pi \rho^{2} n_{1}I_{1}(t) ----(4)

We have to find electromotive force E₂(t) induced across the entirety of solenoid 2 by the change in current in solenoid 1, i.e.

                       E_{2} (t) = -n_{2}L\frac{d \phi_{1}}{dt} ---- (5)

substituting (4) in (5)

E_{2} (t) = -n_{2}L\frac{d }{dt}(\mu_o} \pi \rho^{2} n_{1}I_{1}(t))\\E_{2} (t) = -\pi\mu_o} \rho^{2} n_{1}n_{2}L\frac{d }{dt}I_{1}(t)

5 0
3 years ago
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