You can find the emf of the battery by using:
Q = CV.
Q = Charge in capacitor plates = 30μC
C = Capacitance of the capacitor = 30μF
V = Q/C = 30/30 = 1V
Ans: The emf of the battery = 1V.
I hope that helps you!!!!!!
Answer:
proton proton proton proton
Answer:
Acceleration = Passing a car on the highway/Any change in speed or direction/Slowing down to turn at an intersection
Friction = The force that opposes motion/The wheels moving against the road
Newton's first law = An object in motion stays in motion unless acted on by an outside force
Newton's second law = The harder you kick a ball the faster it will travel
Answer:

Explanation:
Consider two solenoids that are wound on a common cylinder as shown in fig. 1. Let the cylinder have radius 'ρ' and length 'L' .
No. of turns of solenoid 1 = n₁
No. of turns of solenoid 1 = n₂
Assume that length of solenoid is much longer than its radius, so that its field can be determined from Ampère's law throughout its entire length:

We will consider the field that arises from solenoid 1, having n₁ turns per unit length. The magnetic field due to solenoid 1 passes through solenoid 2, which has n₂ turns per unit length.
Any change in magnetic flux from the field generated by solenoid 1 induces an EMF in solenoid 2 through Faraday's law of induction:

Consider B₁(t) magnetic feild generated in solenoid 1 due to current I₁(t)
Using:
--- (2)
Flux generated due to magnetic field B₁
---(3)
area of solenoid = 
substituting (2) in (3)
----(4)
We have to find electromotive force E₂(t) induced across the entirety of solenoid 2 by the change in current in solenoid 1, i.e.
---- (5)
substituting (4) in (5)
