Answer:

Explanation:
As we know that thermal expansion coefficient of aluminium is given as

now we also know that after thermal expansion the final length is given as

here we know that



now we will have


Answer:
11109.825 N
Explanation:
Given Data:
total mass =m=1510 kg
initial acceleration (a) =0.75g ( g=9.81 m/s² )
F=ma
= (1510)*( 0.75*9.81)
= 11109.825 N