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Elis [28]
3 years ago
6

what will be the moment of inertia of a body if it rotates at a uniform rate of 10rad/sec^2 by a torque of 120Nm?​

Physics
1 answer:
Naya [18.7K]3 years ago
7 0

Answer:

12 kgm²

Explanation:

here angular acceleration = 10rad/sec²

torque= 120Nm

moment of inertia=?

we know,

torque= angular acceleration× moment of Inertia

or, moment of inertia = torque/angular acceleration

= 120/10

= 12kgm²

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When a cup is placed on a table, which force prevents the cup from falling to the ground?
zhuklara [117]

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B. normal force

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4 years ago
A 0.3-kg object connected to a light spring with a force constant of 19.3 N/m oscillates on a frictionless horizontal surface. A
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That is,

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• the spring would perform 1/2 (19.3 N/m) (0.019 m)² ≈ 0.0035 J by pushing the object from the 1.9 cm position to equilbrium

so the work done in pushing the object from the 6 cm position to the 1.9 cm position is the difference between these.

By the work-energy theorem,

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3 years ago
Holding onto a tow rope moving parallel to a frictionless ski slope, a 70.1 kg skier is pulled up the slope, which is at an angl
lara [203]

Answer:

given,

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angle with horizontal, θ = 8.6°

magnitude of the force,F = ?

a) Applying newton's second law

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   m g sin\theta - F_{rope} =0

   F_{rope} = m g sin\theta

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