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AysviL [449]
3 years ago
13

Two loudspeakers are placed next to each other and driven by the same source at 500 Hz. A listener is positioned in front of the

two speakers and on the line separating them, thus creating a constructive interference at the listener's ear. What minimum distance would one of the speakers be moved back away from the listener to produce destructive interference at the listener's ear? (The speed of sound = 340 m/s.)
Physics
1 answer:
stellarik [79]3 years ago
7 0

To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is

\lambda = \frac{v}{f}

Here,

v = Wave velocity

f = Frequency,

Replacing with our values we have that,

\lambda = \frac{340}{500}

\lambda = 0.68m

The distance to move one speaker is half this

\lambda/2 = 0.34m

Therefore the minimum distance will be 0.34m

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A proton is moved from the negative to the positive plate of a parallel-plate arrangement. The plates are 1.50 cm apart, and the
Nana76 [90]

(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.

(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

<h3>Potential energy of the proton</h3>

U = qΔV

where;

  • q is charge of the proton
  • ΔV is potential difference

U = q(Ed)

U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)

U = 3.6 x 10⁻¹⁸ J

<h3>Potential difference between the negative plate and a point midway</h3>

ΔV = E(0.5d)

ΔV = 0.5Ed

ΔV = 0.5 (1500)(1.5 x 10⁻²)

ΔV = 11.25 V

<h3>Speed of the proton </h3>

U = ¹/₂mv²

U = mv²

v² = 2U/m

where;

  • m is mass of proton = 1.67 x 10⁻²⁷ kg

v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)

v² = 4.311 x 10⁹

v = √(4.311 x 10⁹)

v = 6.57 x 10⁴ m/s

Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

The potential difference between the negative plate and a point midway between the plates is 11.25 V.

The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

Learn more about potential difference here: brainly.com/question/24142403

#SPJ1

4 0
2 years ago
Electrostatic precipitator in chimneys of factories and hybrid vehicle technology can help in curbing air pollution. How? plzzzz
nexus9112 [7]
It helps reduce the amount of carbon emissions released into the air
<span>An electrostatic precipitator is a filtration device that removes fine particles, like dust and smoke, from a flowing gas using the force of an induced electrostatic charge minimally impeding(slowing down) the flow of gases through the unit.
</span>
a device for removing small particles, as of smoke, dust, or oil, from a gas, as air, by passing the gas first through an electrically charged screen that gives a charge to the particles, then between two charged plates where the particles are attracted to one <span>surface.
</span>http://www.britannica.com/technology/electrostatic-precipitator

7 0
3 years ago
Block 1, of mass m1 = 1.30 kg , moves along a frictionless air track with speed v1 = 27.0 m/s . It collides with block 2, of mas
Dennis_Churaev [7]

(A) The total initial momentum of the system is

(1.30 kg) (27.0 m/s) + (23.0 kg) (0 m/s) = 35.1 kg•m/s

(B) Momentum is conserved, so that the total momentum of the system after the collision is

35.1 kg•m/s = (1.30 kg + 23.0 kg) <em>v</em>

where <em>v</em> is the speed of the combined blocks. Solving for <em>v</em> gives

<em>v</em> = (35.1 kg•m/s) / (24.3 kg) ≈ 1.44 m/s

(C) The kinetic energy of the system after the collision is

1/2 (1.30 kg + 23.0 kg) (1.44 m/s)² ≈ 25.4 J

and before the collision, it is

1/2 (1.30 kg) (27.0 m/s)² ≈ 474 J

so that the change in kinetic energy is

∆<em>K</em> = 25.4 J - 474 J ≈ -449 J

6 0
3 years ago
A 91 kg zebra is traveling 7 m/s east. What is the zebra’s momentum? kg-m/s
frez [133]
To find momentum you multiply the mass and velocity.
91 × 7 = 637 kg-m/s
5 0
3 years ago
Describe what happens when a plate carrying oceanic crust collides with a plate carrying continental crust.
pav-90 [236]

Answer:

Subduction occurs and a trench is formed.

Explanation:

  • When a tectonic plate carrying an oceanic crust collides with a tectonic plate carrying a continental crust then the oceanic plate will slide beneath the continental one, forming a trench.
  • This is possible because the oceanic crust is less dense than the continental crust.

Subduction is a geological phenomenon in which the tectonic plates of one crustal plate descends below the edge of the other. The region where this happens is called a subduction zone.

3 0
3 years ago
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