The plane of the ecliptic is an imaginary plane that passes from the Sun through the Earth. So Earth has an inclination of zero degrees from the plane.
All planets of our Solar System do not lie in this imaginary plane.
Mars is less than 2 degrees off which is why it appears to be centralized. Jupiter is also less than 2 degrees off. But some such as the Plutoid or Dwarf Planet Pluto can be off as much as 17 degrees.
Hope this gives you a bit understanding!
According to Ohm's law,
R=V/I
∴I=V/R.
Power supplied to resistor = VI
= V×V/R = V²/R.
(If you don’t understand, I will try to explain to you again!)
Answer:
The expression for the initial speed of the fired projectile is:
![\displaystyle v_0=\frac{M+m}{m}(2gL[1-cos(\theta)]^{\frac{1}{2}})](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v_0%3D%5Cfrac%7BM%2Bm%7D%7Bm%7D%282gL%5B1-cos%28%5Ctheta%29%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29)
And the initial speed ratio for the 9.0mm/44-caliber bullet is 1.773.
Explanation:
For the expression for the initial speed of the projectile, we can separate the problem in two phases. The first one is the moment before and after the impact. The second phase is the rising of the ballistic pendulum.
First Phase: Impact
In the process of the impact, the net external forces acting in the system bullet-pendulum are null. Therefore the linear momentum remains even (Conservation of linear momentum). This means:
(1)
Second Phase: pendular movement
After the impact, there isn't any non-conservative force doing work in al the process. Therefore the mechanical energy remains constant (Conservation Of Mechanical Energy). Therefore:
(2)
The height of the pendulum respect L and θ is:
(3)
Using equations (1),(2) and (3):
(4)
The initial speed ratio for the 9.0mm/44-caliber bullet is obtained using equation (4):
