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AysviL [449]
3 years ago
13

Two loudspeakers are placed next to each other and driven by the same source at 500 Hz. A listener is positioned in front of the

two speakers and on the line separating them, thus creating a constructive interference at the listener's ear. What minimum distance would one of the speakers be moved back away from the listener to produce destructive interference at the listener's ear? (The speed of sound = 340 m/s.)
Physics
1 answer:
stellarik [79]3 years ago
7 0

To solve this problem we will apply the concepts related to wavelength as the rate of change of the speed of the wave over the frequency. Mathematically this is

\lambda = \frac{v}{f}

Here,

v = Wave velocity

f = Frequency,

Replacing with our values we have that,

\lambda = \frac{340}{500}

\lambda = 0.68m

The distance to move one speaker is half this

\lambda/2 = 0.34m

Therefore the minimum distance will be 0.34m

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The orbit of mars is never far from the ecliptic. why?
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The plane of the ecliptic is an imaginary plane that passes from the Sun through the Earth. So Earth has an inclination of zero degrees from the plane.

All planets of our Solar System do not lie in this imaginary plane.

Mars is less than 2 degrees off which is why it appears to be centralized. Jupiter is also less than 2 degrees off. But some such as the Plutoid or Dwarf Planet Pluto can be off as much as 17 degrees.


Hope this gives you a bit understanding!
7 0
3 years ago
What is the power p supplied to a resistor whose resistance is r when it is known that it has a voltage δv across it?
FromTheMoon [43]
According to Ohm's law,
R=V/I
∴I=V/R.
Power supplied to resistor = VI
                                           = V×V/R = V²/R.

8 0
3 years ago
A helicopter flying horizontally at a height H with a speed v0needs to drop a supply capsule to a point P . Assume the capsule h
irinina [24]
L = V0 x t
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7 0
2 years ago
Please help !!! anyone​
yulyashka [42]
(If you don’t understand, I will try to explain to you again!)

4 0
3 years ago
In a ballistic pendulum an object of mass m is fired with an initial speed v0 at a pendulum bob. The bob has a mass M, which is
Anarel [89]

Answer:

The expression for the initial speed of the fired projectile is:

\displaystyle v_0=\frac{M+m}{m}(2gL[1-cos(\theta)]^{\frac{1}{2}})

And the initial speed ratio for the 9.0mm/44-caliber bullet is 1.773.

Explanation:

For the expression for the initial speed of the projectile, we can separate the problem in two phases. The first one is the moment before and after the impact. The second phase is the rising of the ballistic pendulum.

First Phase: Impact

In the process of the impact, the net external forces acting in the system bullet-pendulum are null. Therefore the linear momentum remains even (Conservation of linear momentum). This means:

P_0=P_f\\v_0m=v_i(m+M)\\v_0=v_i\frac{m+M}{m}  (1)

Second Phase: pendular movement

After the impact, there isn't any non-conservative force doing work in al the process. Therefore the mechanical energy remains constant (Conservation Of Mechanical Energy). Therefore:

Em_i=Em_f\\\frac{1}{2}mv^2_i=mgH\\v_i=[2gH]^\frac{1}{2}  (2)

The height of the pendulum respect L and θ is:

H=L(1-cos(\theta)) (3)

Using equations (1),(2) and (3):

\displaystyle v_0=\frac{M+m}{m}(2gL[1-cos(\theta)]^{\frac{1}{2}}) (4)

The initial speed ratio for the 9.0mm/44-caliber bullet is obtained using equation (4):

\displaystyle \frac{v_{9mm}}{v_{44}} =\frac{(M+m_{9mm})m_{44}}{(M+m_{44})m_{9}}(\frac{1-cos(\theta_{9mm})}{1-cos(\theta_{44})} )^{\frac{1}{2}}=1.773

5 0
3 years ago
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