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marysya [2.9K]
3 years ago
9

determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
Data:

m = 35g
Q = 48 j
T1 = 298K
T2 = 313K
Cs = ?

Fórmula: Q = m*Cs*(T2 - T1) => Cs = Q / [m (T2 - T1)]

Cs = 48 j / [35g (313K - 298K] = 0.0914 j / g*K = 91.4 j / kg*K
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Ivahew [28]

The solution would be like this for this specific problem:

 

<span>Moles of carbon = 58.8 / 12 = 4.9 </span><span>
<span>Moles of hydrogen = 9.8 / 1 = 9.8 </span>
<span>Moles of oxugen = 31.4 / 16 m= 1.96 </span>
<span>Ratio 4.9 / 1.96 = 2.5 9.8 / 1.96 = 5.0 1.96 / 1.96 = 1 </span></span>

Simplest formula = C5H10<span>


</span><span>I hope this helps and if you have any further questions, please don’t hesitate to ask again.</span>
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2 years ago
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Solve the equation 5m+4=7m+6​
ioda
The equation of 5m+4=7m+6 is equal to m=-1
7 0
3 years ago
Calculate the initial rate for the formation of C at 25 ∘C, if [A]=0.50M and [B]=0.075M.Express your answer to two significant f
N76 [4]

The question is incomplete, here is the complete question:

Calculate the initial rate for the formation of C at 25°C, if [A]=0.50 M and [B]=0.075 M. Express your answer to two significant figures and include the appropriate units.Consider the reaction

A + 2B ⇔ C

whose rate at 25°C was measured using three different sets of initial concentrations as listed in the following table:

The table is attached below as an image.

<u>Answer:</u> The initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+2B\rightleftharpoons C

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

  • Expression for rate law for first trial:

5.4\times 10^{-3}=k(0.30)^a(0.050)^b ....(1)

  • Expression for rate law for second trial:

1.1\times 10^{-2}=k(0.30)^a(0.100)^b ....(2)

  • Expression for rate law for third trial:

2.2\times 10^{-2}=k(0.50)^a(0.050)^b ....(3)

Dividing 2 by 1, we get:

\frac{1.1\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.30)^a(1.00)^b}{(0.30)^a(0.050)^b}\\\\2=2^b\\b=1

Dividing 3 by 1, we get:

\frac{2.2\times 10^{-2}}{5.4\times 10^{-3}}=\frac{(0.50)^a(0.050)^b}{(0.30)^a(0.050)^b}\\\\4.07=2^a\\a=2

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^1       ......(4)

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

5.4\times 10^{-3}=k[0.30]^2[0.050]^1\\\\k=1.2M^{-2}s^{-1}

Calculating the initial rate of formation of C by using equation 4, we get:

k=1.2M^{-2}s^{-1}

[A] = 0.50 M

[B] = 0.075 M

Putting values in equation 4, we get:

\text{Rate}=1.2\times (0.50)^2\times (0.075)^1\\\\\text{Rate}=2.25\times 10^{-2}Ms^{-1}

Hence, the initial rate for the formation of C at 25°C is 2.25\times 10^{-2}Ms^{-1}

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Copper sulfate can crystalize as an anhydrate (no water in the crystal) or as three different hydrates (varying amounts of water
Maurinko [17]

Answer:

Two factors that might have a affect of which copper sulphate mineral will occur at a given location  is:

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B. Also it binds nicely with the sediments  or the crystal.

Explanation:

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So, the two factors that might give an affect which type of copper sulphate  mineral willoccur at a given location is:

A. The copper sulphate high solubility in water.

B. It binds extremely nicely with the sediments or say to the crystal. It is  also regulated by plants.

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3 years ago
A carpet sells for 27.99 a square yard. What is the price of the carpet square per square meter ?
klio [65]
There are 9 square meters in one square yard so divide 27.99 by 9

27.99/9=3.11

one square meter is $3.11

I hope I've helped!
3 0
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