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marysya [2.9K]
3 years ago
9

determine the specific heat of a mayterial if a 35g sample of the material absorbs 48J as it is heated from 298K to 313K

Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
Data:

m = 35g
Q = 48 j
T1 = 298K
T2 = 313K
Cs = ?

Fórmula: Q = m*Cs*(T2 - T1) => Cs = Q / [m (T2 - T1)]

Cs = 48 j / [35g (313K - 298K] = 0.0914 j / g*K = 91.4 j / kg*K
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6 0
3 years ago
a gas in a container with a fixed volume was originally at a pressure of 317kpa and a temperature of 154k. what is the new press
goldfiish [28.3K]
<h2>Hello!</h2>

The answer is: 4.77atm

<h2>Why?</h2>

Since there's a fixed volume, we can use the the Gay-Lussac's Law which stablish a relation between the pressure and the temperature:

\frac{P}{T}=k

<em>P</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

We also have the following equation:

\frac{P1}{T1}=\frac{P2}{T2}

Where:

P2=\frac{P1*T2}{T1}=\frac{317kPa*235K}{154K}=483.73kPa

We are asked to find the pressure in atm, so we must convert 483.73kPa to atm:

1kPa=0.009869atm

Then,

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Have a nice day!

8 0
3 years ago
How does a sample of water at 38 °C compare to a sample of water at 295 K?
Sidana [21]

Converting the temperature, 295 K from Kelvin to Celsius scale:

295 K - 273 = 22^{0} C

Water has a boiling point of 100^{0}C and a melting point of 0^{0} C

When we compare water at two different temperatures, 22^{0}C and 38^{0}C we can say that water is in liquid form at both these temperatures as both of them are quite below the boiling temperature and above the melting temperature.

The temperature difference between water at the given two temperatures = 38^{0}C - 22^{0}C = 16^{0}C

Water at 38^{0}C is at a higher temperature and so is warmer than water at a lower temperature of 22^{0}C (or 295 K).


7 0
3 years ago
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