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Rina8888 [55]
3 years ago
12

What is the average velocity of a car address for my .7 m to 2 m away from the garage in 3 seconds

Physics
1 answer:
stepan [7]3 years ago
5 0

Answer:

v=\frac{5}{3}

Explanation:

So average velocity is calculated as

average velocity=\frac{total displacement}{total time}

Hence in our given case total displacement would be 5 m as the car moves a distance 7m to 2m.

Time taken for this moment is given to be 3 seconds.

Hence substituting back we get the average velocity as

v=\frac{5}{3}

Hence this is the average velocity in this case.

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If it produces 20J of light energy in a second, then that 20J is the 10% of the supply that becomes useful output.

20 J/s = 10% of Supply

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Divide each side by 0.1:

Supply = (20 J/s) / (0.1)

<em>Supply = 200 J/s  </em>(200 watts)

========================

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