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Vikentia [17]
3 years ago
9

What is the pOH of a solution that has a hydronium ion concentration [H3O+] of 8.26 x 10–5 M

Chemistry
1 answer:
viva [34]3 years ago
6 0

Answer:

The pOH of the solution is 9.92

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance. PH is defined as the negative logarithm (base 10) of the hydronium ion concentration [H₃O⁺]:

pH= - log [H₃O⁺]

So, if [H₃O⁺]=8.26*10⁻⁵, the pH is: pH=- log (8.26*10⁻⁵) ⇒ pH= 4.08

The pOH measures the concentration of OH− ions. The following relationship can be established between pH and pOH:

pH + pOH= 14

In this case, being pH=4.08  and replacing in the relationship between pH and pOH:

4.08 + pOH=14

Solving:

pOH= 14 - 4.08

pOH= 9.92

The pOH of the solution is 9.92

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To what Kelvin temperature must a balloon
snow_tiger [21]

Answer:

T_2=261.46\ K

Explanation:

It is given that,

Original temperature, T_1=323^{\circ}C=596.15\ K

Original volume, V_1=2.85\ L

We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.

According to Charles law, at constant pressure, V\propto T

It would means, \dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

T₂ = ?

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.25\times 596.15}{2.85}\\\\T_2=261.46\ K

So, the new temperature is 261.46 K.

4 0
3 years ago
The pH of a 1.0M solution of butanoic acid HC4H7O2 is measured to be 2.41. Calculate the acid dissociation constant Ka of butano
Lubov Fominskaja [6]

Answer:

Ka = 1.52 E-5

Explanation:

  • CH3-(CH2)2-COOH ↔ CH3(CH2)2COO-  + H3O+

⇒ Ka = [H3O+][CH3)CH2)2COO-] / [CH3(CH2)2COOH]

mass balance:

⇒<em> C</em> CH3(CH2)2COOH = [CH3(CH2)2COO-] + [CH3(CH2)2COOH] = 1.0 M

charge balance:

⇒ [H3O+] = [CH3(CH2)2COO-]

⇒ Ka = [H3O+]²/(1 - [H3O+])

∴ pH = 2.41 = - Log [H3O+]

⇒ [H3O+] = 3.89 E-3 M

⇒ Ka = (3.89 E-3)² / ( 1 - 3.89 E-3 )

⇒ Ka = 1.519 E-5

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3 years ago
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3 years ago
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An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

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3 years ago
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zhenek [66]
The answer would be kinetic energy. :)
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3 years ago
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