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Vikentia [17]
3 years ago
9

What is the pOH of a solution that has a hydronium ion concentration [H3O+] of 8.26 x 10–5 M

Chemistry
1 answer:
viva [34]3 years ago
6 0

Answer:

The pOH of the solution is 9.92

Explanation:

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance. PH is defined as the negative logarithm (base 10) of the hydronium ion concentration [H₃O⁺]:

pH= - log [H₃O⁺]

So, if [H₃O⁺]=8.26*10⁻⁵, the pH is: pH=- log (8.26*10⁻⁵) ⇒ pH= 4.08

The pOH measures the concentration of OH− ions. The following relationship can be established between pH and pOH:

pH + pOH= 14

In this case, being pH=4.08  and replacing in the relationship between pH and pOH:

4.08 + pOH=14

Solving:

pOH= 14 - 4.08

pOH= 9.92

The pOH of the solution is 9.92

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<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg

<em>Molar concentration </em>

Assume you have 1 L solution.

Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)

= 1190 g solution

Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)

= 84.01 g NaHCO3

Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)

= 1.14 mol NaHCO3

<em>c</em> = 1.14 mol/1 L = 1.14 mol/L

<em>Molal concentration</em>

Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg

<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg

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3 years ago
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According to which theory or law is a chemical reaction most likely to occur when two particles with the proper energy and orien
Nat2105 [25]
<h2>Collision Theory </h2>

Explanation:

<h3>The given statement is related to the collision theory - </h3>

Collision theory was given by William Lewis in 1916.

This theory explains in a qualitative manner that in what way any chemical reaction occurs and the reason for the different reaction rates for different reactions.

<h3>According to the collision theory - </h3>
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  • Sufficient amount of energy is needed for collisions (kinetic energy) so that the chemical bonds should break
  • This energy used is known as the activation energy
  • On the increase in the temperature, the kinetic energy of the molecule increases and the molecules move faster and collide with a proper orientation at an increased speed
  • This increases the rate of a collision that in turn increases the breaking of the bond  

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Helium gas collected at a pressure of 0.0045 atm is put into a flexible balloon measuring 350 mL in volume. What volume, in mL,
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<span>Hello!
 
The statement that best proves that the law of conservation is obeyed during this process is that </span><span>The total mass of oxygen and carbon is equal to the total mass of carbon dioxide.

The chemical equation for the combustion reaction of coal in the carbon cycle is the following one:

C(s) + O</span>₂(g) → CO₂(g)
<span>
From this simple chemical equation, we can conclude that if the Law of Conservation of Matter is obeyed in this reaction, the sum of the initial masses of Carbon and Oxygen before the reaction will be equal to the total amount of Carbon Dioxide formed by it, because they sum up to produce Carbon Dioxide.

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3 years ago
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PLEASE HELP! 25 POINTS!!!! I got the #1, just not #2 and #3. An industrial chemical company has opened a new plant that will pro
podryga [215]

Answer :

Part 1 : Balanced reaction, 3H_2(g)+N_2(g)\rightarrow 2NH_3(g)

Part 2 : The theoretical yield of NH_3 gas = 440.96 g

Part 3 : The % yield of ammonia is 90.03 %

Solution : Given,

Mass of N_2 = 475 g

Molar mass of N_2 = 28 g/mole

Molar mass of NH_3 = 17 g/mole

Experimental yield of NH_3 = 397 g

<u>Answer for Part (1) :</u>

The balanced chemical reaction is,

3H_2(g)+N_2(g)\rightarrow 2NH_3(g)

<u>Answer for Part (2) :</u>

First we have to calculate the moles of N_2.

\text{Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molecular mass of }N_2}=\frac{475g}{28g/mole}=16.96moles

From the given reaction, we conclude that

1 moles of N_2 gas react to give 2 moles of NH_3 gas

16.96 moles of N_2 gas react to give \frac{2}{1}\times 16.96=33.92 moles of NH_3 gas

Now we have to calculate the mass of NH_3 gas.

\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3

\text{ Mass of }NH_3=(33.92moles)\times (17g/mole)=440.96g

Therefore, the theoretical yield of NH_3 gas = 440.96 g

<u>Answer for Part (3) :</u>

Formula used for percent yield :

\% \text{ yield of }NH_3=\frac{\text{ Experimental yield of }NH_3}{\text{ Theoretical yield of }NH_3}\times 100

\% \text{ yield of }NH_3=\frac{397g}{440.96g}\times 100=90.03\%

Therefore, the % yield of ammonia is 90.03 %

3 0
3 years ago
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