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4 years ago

there are about 1.5 grams of fat in 1 tabespoon of humus.how many grams of fat are in 2 1/2 cups of hummus ?

1 answer:

6 0

We'll first we need to know the in 1 cup there is 16 tablespoon.
so we could multiply we need 2 1/2 cup so that is 16 (1cup) + 16 (1cup) +8 (1/2 cup)= 40 tablespoons... and 1 tablespoon is 1.5 grams of fat then we multiply 40 times 1.5 .... This is equal to 60 grams fat
So there is 60 grams of fat in 2 1/5 cups of hummus.

You might be interested in

Find the greatest common factor of x²y and xy²

balandron [24]

Answer:

Step-by-step explanation:

Let's take a look at what factors $x^2y$ and $xy^2$ have in common.

$x^2y$ is composed of $x^2$ and y, and $xy^2$ is composed of x and $y^2$ . Notice that both x and y are factors of them, so the gcf is xy.

8 0

3 years ago

Suppose that E and F are two events and that Upper P (Upper E and Upper F )equals0.3 and Upper P (Upper E )equals0.5. What is Up

m_a_m_a [10]

Answer:

$P(\frac{F}{E}) =\frac{0.3}{0.5} =0.6$

Step-by-step explanation:

Step 1:-

Suppose that E and F are two events and that P(E n F) = 0.3

also given P(E) =0.5

Conditional probability:-

if E₁ and E₂ are two events in a Sample S and P(E₁)≠ 0, then the probability of E₂ , after the event E₁ has occurred, is called the Conditional probability

of the event E₂ given E₁ and is denoted by

$P(\frac{F}{E}) = \frac{P(EnF)}{P(E)}$

$P(\frac{F}{E}) =\frac{0.3}{0.5} =0.6$

6 0

3 years ago

The Municipal Transit Authority wants to know if, on weekdays, more passengers ride the northbound blue line train towards the c

Kitty [74]

Answer:

The 90% confidence interval $-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

The distribution test statistics is $t = -3.222$

The rejection region is p-value < $\alpha$

The decision rule is reject the null hypothesis

The conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

The p-value is $p-value =0.000951$

Step-by-step explanation:

From the question we are told that

The first sample size $n_1 = 30$

The first sample mean is $\= x _1 = 323$

The first standard deviation is $s_1 = 41$

The second sample size is $n_2 = 45$

The second sample mean is $\=x_2 = 356$

The second standard deviation is $s_2 = 45$

given that the confidence level is 90% then the level of significance is mathematically represented as

$\alpha = (100 -90)\%$

$\alpha = 0.10$

Generally the critical value of $\frac{\alpha }{2}$ obtained from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the pooled variance is mathematically represented as

$s^2 = \frac{(n_1 - 1)s_1^2 + (n_2 -1)s_2^2 }{n_1 + n_2 -2}$

$s^2 = \frac{(30 -1)(41^2) + (45-1)45^2}{30+45 -2}$

$s^2 = 1888.34$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s^2}{n_1} + \frac{s^2}{n_2} }$

=> $SE = \sqrt{\frac{1888.34}{30} + \frac{1888.34}{45} }$

=> $SE = 10.24$

Generally the margin of error is mathematically evaluated as

$E = Z_{\frac{\alpha }{2} } * SE$

$E = 1.645* 10.24$

$E = 16.85$

Generally the 90% confidence interval is mathematically represented as

$\=x_1 -\=x_2 -E < \mu_1 -\mu_2 < \=x_1 -\=x_2 +E$

$323 -356 -16.84$

$-49.8$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 < \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \=x_2 }{SE}$

=> $t = \frac{323-356}{10.24}$

=> $t = -3.222$

Generally the degree of freedom is mathematically represented as

$df = n_1+n_2 -2$

$df = 30 + 45 -2$

$df = 73$

The p-value is obtained from the student t distribution table at degree of freedom of 73 at 0.05 level of significance

The value is $p-value =0.000951$

Here the level of significance is $\alpha = 5\% = 0.05$

Given that the p-value < $\alpha$ then we reject the null hypothesis

Then the conclusion is

There is sufficient evidence to conclude that there are more passengers riding the 8:30 train

5 0

3 years ago

Sam is paid time and a half for overtime, if his basic hourly rate is $12.50 and he works 8 hours overtime, how much did he earn

Vesna [10]

It would be $100 if he works for eight hour hours if it wasn’t overtime but since it’s overtime and he works half of the amount it would be 50

5 0

3 years ago

Please help !!! I’m stuck

Kruka [31]

Answer:

2/3 ≈ 0.6667

Step-by-step explanation:

apply soh cah toa

sine=opposite/hypo

sine=4/6

sine=2/3

4 0

3 years ago