Answer:To establish the age of a rock or a fossil, researchers use some type of clock to determine the date it was formed. Geologists commonly use radiometric dating methods, based on the natural radioactive decay of certain elements such as potassium and carbon, as reliable clocks to date ancient events.
Explanation:
Answer:
1.27
Explanation:
Period of a pendulum T is
T = 2¶(l/g)^0.5
Where g is acceleration due to gravity
l is lenght of pendulum
For earth, T = 2.243 s
2.243 = 2 x 3.142 x (l/9.81)^0.5
0.36 = (l^0.5)/3.13
1.13 = l^0.5
l = 1.28 m
For planet X of the same lenght
Period T = 2.00 s
2 = 2 x 3.142 (1.28/gx)^0.5
0.32 = 1.13 / gx^0.5
3.53 = gx^0.5
gx^0.5 = 3.53
gx = 12.46 m/s^2
gx/gearth = 12.46/9.81 = 1.27
Answer:
Explanation:
Given
mass of satellite
orbital radius
mass of Earth
Minimum amount of Energy to move Satellite from its orbit to an infinite distance is sum of Potential Energy + Kinetic Energy of Satellite
Where
i.e. Energy is required to provide to move Satellite out of its orbit
Answer:
350 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) of Go Kart = 35 kg
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Force (F) =?
Next, we shall determine the acceleration of the Go Kart. This can be obtained as follow:
Initial velocity (u) = 12 m/s
Distance (s) = 7.2 m
Final velocity (v) = 0 m/s
Acceleration (a) =.?
v² = u² + 2as
0² = 12² + (2 × a × 7.2)
0 = 144 + 14.4a
Collect like terms
0 – 144 = 14.4a
– 144 = 14.4a
Divide both side by 14.4
a = – 144 / 14.4
a = – 10 m/s²
The negative sign indicate that the Go Kart is decelerating when the brake was applied.
Finally, we shall determine the force the Go Kart have when the student locked the brake. This can be obtained as follow:
Mass (m) of Go Kart = 35 kg
Acceleration (a) = 10 m/s
Force (F) =?
F = ma
F = 35 × 10
F = 350 N
Thus, the Go Kart has a force of 350 N when the student locked the brake.
Answer:
The second material's index of refraction is 1.17.
Explanation:
Given that,
Refractive index of the material, n = 1.29
Critical angle is 65.9 degrees.
We need to find the second material's index of refraction. We know that at critical angle of incidence, angle of refraction is equal to 90 degrees. Using Snell's law as:
So, the second material's index of refraction is 1.17.