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3241004551 [841]
4 years ago
12

How are the electric field lines around a positive charge affected when a second positive charge is near it? The field lines com

bine with the lines around the second positive charge. The field lines overlap with the lines from the second positive charge. The field lines bend toward the second positive charge. The field lines bend away from the second positive charge. WILL MARK BRAINILEST 
Physics
2 answers:
barxatty [35]4 years ago
8 0

Answer:

D

Explanation:

timofeeve [1]4 years ago
3 0
The answer would be D hope it helps and sorry if it is wrong.  :)
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An 880n box is pushed across a level floor for a distance of 5.0m with a force of 440n. how much work was done on the box
Simora [160]
W=Fd, F=440N, d=5m. 5x440=2,200J of work
8 0
4 years ago
Read 2 more answers
A graduated beaker with 375 mL of water is sitting on a scale which measures the weight of the glass and water to be 7.60 N. Whe
Allisa [31]

Answer:

Volume of water displaced = 450 - 375 = 75 ml

Vr = volume of rock = 75 ml

Wr = 9.22 - 7.60 = 1.62 N  weight of 75 ml of rock

Density of rock = 1.62 N / 75 ml = .0216 N / ml

Density of water = 1000 g / 1000 ml = 9.8 N / 1000 ml = .0098 N / ml

Density of rock / density of water = .0216 / .0098 = 2.20

8 0
3 years ago
An 820 N Marine in basic training climbs a 12.0-m vertical rope at a constant speed in 8.00 s. What is her power output
sweet-ann [11.9K]

Answer:

1230 W

Explanation:

P = \frac{W}{t} = \frac{Force * distance}{time} = \frac{820 N * 12.0 m}{8.00 s} = 1230 Watts

6 0
4 years ago
38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari
kolbaska11 [484]

Answer:

Final volumen first process V_{2} = 98,44 cm^{3}

Final Pressure second process P_{3} = 1,317 * 10^{10} Pa

Explanation:

Using the Ideal Gases Law yoy have for pressure:

P_{1} = \frac{n_{1} R T_{1} }{V_{1} }

where:

P is the pressure, in Pa

n is the nuber of moles of gas

R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

n_{1} = n_{2} = n

In an isobaric process the pressure is constant so:

P_{1} = P_{2}

\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }

\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }

V_{2} = \frac{T_{2} V_{1} }{T_{1} }

Replacing : T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}

V_{2} = 98,44 cm^{3}

Replacing on the ideal gases formula the pressure at this piont is:

P_{2} = 3,92 * 10^{9} Pa

For Temperature the ideal gases formula is:

T = \frac{P V }{n R }

For the second process you have that T_{2} = T_{3}  So:

\frac{P_{2} V_{2} }{n R } = \frac{P_{3} V_{3} }{n R }

P_{2} V_{2}  = P_{3} V_{3}

P_{3} = \frac{P_{2} V_{2}}{V_{3}}

P_{3} = 1,317 * 10^{10} Pa

7 0
3 years ago
There is no law of conservation​
ruslelena [56]

Answer:

yes

Explanation:

I think so because it not mention in the law

3 0
3 years ago
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