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butalik [34]
3 years ago
8

Explain one reason why OHS is important on a farm.​

Physics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

OHS is important because it protects all laborers and employers from harm and health risks caused by their occupations. Â In every working environment, it needs to be safe and conducive to the workers so that there will be a productive output from the workers.

Explanation:

Hope this helps :)

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The brakes on a bicycle apply 95 N of force to the wheels. When the
Veronika [31]

Answer:

idk

Explanation:

idk

6 0
3 years ago
If the total momentum of a system is changing:
DENIUS [597]

Answer:

(d) a net external force must be acting on the system

Explanation:

Momentum is given as the product of mass and velocity.

P = MV

According to Newton's second law of motion, " Force applied to a body (system) is directly proportional to the rate of change of momentum of the body (system) which takes place in the direction of the applied force (external force).

F ∝ΔMV

Therefore, If the total momentum of a system is changing, a net external force must be acting on the system.

(d) a net external force must be acting on the system

3 0
3 years ago
The rectangular boat shown below has base dimensions 10.0 cm × 8.0 cm. Each cube has a mass of 40 g, and the liquid in the tank
Paladinen [302]

When boat is sunk into the liquid the net buoyancy on the boat is counterbalanced by weight of the boat

So here weight of the boat = Buoyancy force

let say boat is sunk by distance "h"

now we can say

F_b = \rho * V * g

F_b = 1000*0.10 * 0.08 * h * 9.8

now by above force balance equation we can write

m*g = F_b

0.040 * 9.8 = 1000 * 0.10 * 0.08 * h * 9.8

0.040 = 8h

h = 5 * 10^{-3} m

so boat will sunk by total 5 mm distance

8 0
3 years ago
Water flowing through a cylindrical pipe suddenly comes to a section of the pipe where the diameter decreases to 86% of its prev
masha68 [24]

Answer:

The speed in the smaller section is 43.2\,\frac{m}{s}

Explanation:

Assuming all the parts of the pipe are at the same height, we can use continuity equation for incompressible fluids:

\Delta Q=0 (1)

With Q the flux of water that is Av with A the cross section area and v the velocity, so by (1):

A_{2}v_{2}-A_{1}v_{1}=0

subscript 2 is for the smaller section and 1 for the larger section, solving for v_{2}:

v_{2}=\frac{A_{1}v_{1}}{A_{2}} (2)

The cross section areas of the pipe are:

A_{1}=\frac{\pi}{4}d_{1}^{2}

A_{2}=\frac{\pi}{4}d_{2}^{2}

but the problem states that the diameter decreases 86% so d_{2}=0.86d_{1}, using this on (2):

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\approx1.35v_{1}

v_{2}\approx(1.35)(32)\approx43.2\,\frac{m}{s}

5 0
3 years ago
Homework
yarga [219]

Answer:

Please reframe your questions

4 0
2 years ago
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