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erastova [34]
3 years ago
11

A dragster takes off from rest and crosses the finish line 320 m away. If the dragster is able to accelerate at 10LaTeX: \frac{m

}{s^2}m s 2 then how long does it take to finish?
Physics
2 answers:
Ber [7]3 years ago
4 0

Answer:

t = 8 s

Explanation:

Rasek [7]3 years ago
3 0

Answer:

t = 8 s

Explanation:

In order to find the time taken by the dragster we will use equations of motion. Here, we will use second equation of motion:

s = Vi t + (1/2)at²

where,

s = distance covered = 320 m

Vi = Initial Velocity = 0 m/s (Since, dragster starts from rest)

t = time taken = ?

a = acceleration of dragster = 10 m/s²

Therefore,

320 m = (0 m/s)t + (1/2)(10 m/s²)t²

t² = (320 m)(2)/(10 m/s²)

t = √(64 s²)

<u>t = 8 s</u>

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Explanation:

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P = 33.3 psi

004 (part 1 of 2)

Since the collisions are elastic, the angle of reflection is the same as the angle of incidence (it bounces off at the same angle).

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3 years ago
A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu
Setler79 [48]
<h2>Given :</h2>

  • total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

1.6 \times 10 {}^{ - 19} \:  C

For producing 1 Cuolomb charge we need :

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  • \dfrac{10\times 10 {}^{19} }{16}

  • \dfrac{100 \times 10 {}^{18} }{16}

  • \mathrm{6.24 \times 10 {}^{18}  \:  \: electrons}

Now, for producing 0.009 C of charge, the number of electrons required is :

  • 0.009 \times 6.24 \times  {10}^{18}

  • 0.05616 \times 10 {}^{18}

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_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

\mathrm{5.616 \times 10 {}^{16} \:  \: electrons}

Number of electrons passing through it in 1 Second is :

  • \dfrac{5.616 \times  {10}^{16} }{3.6}

  • \mathrm{1.56 \times 10 {}^{16}  \:  \: electrons}

Now, in 10 seconds the number of electrons passing through it is :

  • 10 \times  \mathrm{1.56 \times 10 {}^{16}  \:  \: }

  • \mathrm{1.56 \times 10 {}^{17}  \:  \: electrons}

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\mathrm{ \#TeeNForeveR}

6 0
2 years ago
While driving down the road, a grasshopper strikes the windshield of a bus and makes a mess in front of the face of the driver.
nlexa [21]

Answer:

The force on the grass hopper is equal and opposite to the force on the wind shield.

Explanation:

It is a known fact every action has an equal and opposite reaction. Here the action force is the grasshopper hitting the windshield.

The reaction force is the force exerted by the windshield on the grasshopper.

If the force of windshield on the grasshopper is more, grasshopper would have been thrown away. If the grasshopper's force on the windshield is greater, the windshield would have broken.

But here these constitute equal and opposite action-reaction pair of forces and so the grasshopper is able to repeatedly strike the windshield.

3 0
3 years ago
Read 2 more answers
While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per sec
mariarad [96]

The acceleration of the jet is 11.4 m/s^2

Explanation:

Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:

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For the jet in this problem, we have

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Solving for a, we find the acceleration:

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brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

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