Answer:
c. 48 cm/s/s
Explanation:
Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?
from newtons second law of motion ,
which states that change in momentum is directly proportional to the force applied.
we can say that
f=m(v-u)/t
a=acceleration
t=time
v=final velocity
u=initial velocity
since a=(v-u)/t
f=m*a
force applied is F
m =mass of the object involved
a is the acceleration of the object involved
f=m*48.........................1
in the second case ;a mass of 2M when acted upon by a net force of 2F
f=ma
a=2F/2M
substituting equation 1
a=2(M*48)/2M
a=. 48 cm/s/s
Answer:
40 V
Explanation:
I will assume that the resistors are
100 and 3900 and 1000 OHMS <=====(NOT W)
In series , the resistances add together 100 + 3900 + 1000 = 5000 ohms total
V = IR
I = V / R so the total current will be 200 v / 5000 ohms = .04 amps
this is the current through all of the resistors
so for the 1000 ohm resistor V = IR .04 (1000) = 40 V
Answer:
1. 20.54m/s
2. 1.52s
Explanation:
QUESTION 1:
The speed the stone impact the ground is the final speed/velocity, which can be calculated using the formula:
v² = u² + 2as
Where;
v = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration due to gravity (m/s²)
s = distance (m)
From the provided information, u = 5.65m/s, v = ?, s = 19.9m, a = 9.8m/s²
v² = 5.65² + 2 (9.8 × 19.9)
v² = 31.9225 + 2 (195.02)
v² = 31.9225 + 390.04
v² = 421.9625
v = √421.9625
v = 20.5417
v = 20.54m/s
QUESTION 2:
Using v = u + at
Where v = final velocity (m/s) = 20.54m/s
t = time (s)
u = initial velocity (m/s) = 5.65m/s
a = acceleration due to gravity (m/s²)
v = u + at
20.54 = 5.65 + 9.8t
20.54 - 5.65 = 9.8t
14.89 = 9.8t
t = 14.89/9.8
t = 1.519
t = 1.52s
Answer:
Explanation:
First, let's find the voltage through the resistor using ohm's law:
AC power as function of time can be calculated as:
(1)
Where:
Because of the problem doesn't give us additional information, let's assume:
Evaluating the equation (1) in t=3600 (Because 1h equal to 3600s):
