What type of chemical reaction is oil spills?

Why are group 1a (1) and group 2a (2) elements found in many compounds, but not group 8a (18) elements?

Rashid [163]

Because group 1a and 2a are most reactive due to their least number of electrons in their outmost shell compared to group 8a(18)

4 0

2 years ago

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(I)how many atoms are present in 7g of lithium?

ICE Princess25 [194]

Answer :

(i) The number of atoms present in 7 g of lithium are, $6.07\times 10^{23}$

(ii) The number of atoms present in 7 g of lithium are, $1.204\times 10^{24}$

(iii) The number of moles of $F_2$ is, 1 mole

The number of moles of $CO_2$ is, 0.5 mole

The number of moles of $OH^-$ is, 1 mole

Explanation :

Part (i) :

First we have to calculate the moles of lithium.

$\text{Moles of }Li=\frac{\text{Mass of }Li}{\text{Molar mass of }Li}$

Molar mass of Li = 6.94 g/mole

$\text{Moles of }Li=\frac{7g}{6.94g/mol}=1.008mole$

Now we have to calculate the number of atoms present.

As, 1 mole of lithium contains $6.022\times 10^{23}$ number of atoms

So, 1.008 mole of lithium contains $1.008\times 6.022\times 10^{23}=6.07\times 10^{23}$ number of atoms

Thus, the number of atoms present in 7 g of lithium are, $6.07\times 10^{23}$

Part (ii) :

First we have to calculate the moles of carbon.

$\text{Moles of }C=\frac{\text{Mass of }C}{\text{Molar mass of }C}$

Molar mass of C = 12 g/mole

$\text{Moles of }C=\frac{24g}{12g/mol}=2mole$

Now we have to calculate the number of atoms present.

As, 1 mole of carbon contains $6.022\times 10^{23}$ number of atoms

So, 2 mole of carbon contains $2\times 6.022\times 10^{23}=1.204\times 10^{24}$ number of atoms

Thus, the number of atoms present in 7 g of lithium are, $1.204\times 10^{24}$

Part (iii) :

To calculate the moles of $F_2$ :

$\text{Moles of }F_2=\frac{\text{Mass of }F_2}{\text{Molar mass of }F_2}$

Molar mass of $F_2$ = 38 g/mole

$\text{Moles of }F_2=\frac{19g}{19g/mol}=1mole$

Thus, the number of moles of $F_2$ is, 1 mole

To calculate the moles of $CO_2$ :

$\text{Moles of }CO_2=\frac{\text{Mass of }CO_2}{\text{Molar mass of }CO_2}$

Molar mass of $CO_2$ = 44 g/mole

$\text{Moles of }CO_2=\frac{22g}{44g/mol}=0.5mole$

Thus, the number of moles of $CO_2$ is, 0.5 mole

To calculate the moles of $OH^-$ ions :

$\text{Moles of }OH^-=\frac{\text{Mass of }OH^-}{\text{Molar mass of }OH^-}$

Molar mass of $OH^-$ = 17 g/mole

$\text{Moles of }OH^-=\frac{17g}{17g/mol}=1mole$

Thus, the number of moles of $OH^-$ is, 1 mole

4 0

3 years ago

How can scientists practice ethical lab behavior?

olga55 [171]

Answer:

C. By being honest in recording the results of their own experiments

Explanation:

Honesty in recording results is ethical behaviour and the basis of scientific research.

A. is wrong. If you repeat the same experiment, you should always get the same result.

B. is wrong. Copying someone else's results is cheating and certainly unethical behaviour.

D. is wrong. Making up data is dishonest and unethical behaviour.

E. is wrong. Following your own instincts about safety procedures is unethical because your instincts may be wrong. following them may result in injury to yourself or to others.

7 0

3 years ago

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Chemical analysis shows that citric acid contains 37.51% C, 4.20% H, and 58.29% O. What is the empirical formula for citric acid

Fiesta28 [93]

The empirical formula for the citric acid is C₆H₈O₇

<h3>Data obtained from the question </h3>

Carbon (C) = 37.51%

Hydrogen (H) = 4.20%

Oxygen (O) = 58.29%

Empirical formula =?

Divide by their molar mass

C = 37.51 / 12 = 3.126

H = 4.2 / 1 = 4.2

O = 58.29 / 16 = 3.643

Divide by the smallest

C = 3.126 / 3.126 = 1

H = 4.2 / 3.126 = 1.34

O = 3.643 / 3.126 = 1.17

Multiply through by 6 to express in whole number

C = 1 × 6 = 6

H = 1.34 × 6 = 8

O = 1.17 × 6 = 7

Thus, the empirical formula for the citric acid is C₆H₈O₇

Learn more about empirical formula:

brainly.com/question/24818135

7 0

2 years ago

Which of these sources is most likely to be credible when it comes to information on the advantages and disadvantages of using p

Lyrx [107]

Answer:

C

Explanation:

Hope This Helps :)

6 0

3 years ago

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