The distance from the sun to the earth would be which phrase best completes the sentence
1 answer:
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Answer:
How many grams Acetic Acid in 1 mol? The answer is 60.05196.
We assume you are converting between grams Acetic Acid and mole?
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Explanation:
You can view more details on each measurement unit:
molecular weight of Acetic Acid or mol
The molecular formula for Acetic Acid is CH3COOH.
The SI base unit for amount of substance is the mole.
1 grams Acetic Acid is equal to 0.016652245821785 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Acetic Acid and mole.
Examples
1 grams Acetic Acid to mol = 0.01665 mol
10 grams Acetic Acid to mol = 0.16652 mol
20 grams Acetic Acid to mol = 0.33304 mol
30 grams Acetic Acid to mol = 0.49957 mol
40 grams Acetic Acid to mol = 0.66609 mol
50 grams Acetic Acid to mol = 0.83261 mol
100 grams Acetic Acid to mol = 1.66522 mol
200 grams Acetic Acid to mol = 3.33045 mol
Answer:
The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol
Explanation:
The ∆H (heat of reaction) of the combustion reaction is the heat that accompanies the entire reaction. For its calculation you must make the total sum of all the heats of the products and of the reagents affected by their stoichiometric coefficient (number of molecules of each compound that participates in the reaction) and finally subtract them:
Enthalpy of the reaction= ΔH = ∑Hproducts - ∑Hreactants
In this case, you have: 2 NOCl(g) → 2 NO(g) + Cl₂(g)
So, ΔH=
Knowing:
- ΔH= 75.5 kJ/mol
= 90.25 kJ/mol
= 0 (For the formation of one mole of a pure element the heat of formation is 0, in this caseyou have as a pure compound the chlorine Cl₂)
=?
Replacing:
75.5 kJ/mol=2* 90.25 kJ/mol + 0 -
Solving
-=75.5 kJ/mol - 2*90.25 kJ/mol
-=-105 kJ/mol
=105 kJ/mol
<u><em>The standard enthalpy of formation of NOCl(g) at 25 ºC is 105 kJ/mol</em></u>