Use the IUPAC nomenclature rules to give the name for this compound - SiO2

2 answers:

8 0

The compound in IUPAC nomenclature is called Silicon dioxide. It <span> is a chemical compound that is an oxide of silicon with the chemical formula SiO₂. It has been known since ancient times. Hope this answers the question. Have a nice day.</span>

lana [24]3 years ago

3 0

Answer: Name of the given compound $SiO_2$ is silicon dioxide.

Explanation:

Write the name of the cation first. Just write the name of an element which is present as a cation.
Then write the name the anion. The name of the anion is written as name of the element followed by suffix 'ide' in the end.
If more than one number of anion is present in the compound then use prefixes as 'mono' for 1 , 'di' for 2 , 'tri' for 3 and so on.

$SiO_2$ have silicon as cation and two oxygen atom as as anion .So, the name of the of the given compound $SiO_2$ is silicon dioxide.

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You calibrated a different pipet and determined its volume to be 25.40 mL. You then use it to determine the density of an unknow

just olya [345]

Answer:

1148.37401575 kg/m³

Explanation:

Volume of liquid in pipet

25.4 mL

Mass of liquid

$77.8760-48.7073=29.1687\ g$

Density is given by

$\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{29.1687}{25.4}\\\Rightarrow \rho=1.14837401575\ g/ml=1.14837401575\times 10^3=1148.37401575\ kg/m^3$

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4 0

3 years ago

A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v

neonofarm [45]

Total displacement along the length of mountain is given as
L = 235 m
angle of mountain with horizontal = 35 degree
now we will have horizontal displacement as
x = L cos35
x = 235 cos35 = 192.5 m
similarly for vertical displacement we can say
y = L sin35
y = 235 sin35 = 134.8 m

6 0

3 years ago

A 20 kg truck drives in a circle of radius 4 m at 10m/s. What is the centripetal acceleration of the truck?

asambeis [7]

Answer:

B. 25 m/s/s

Explanation:

Centripetal acceleration is the square of the tangential velocity divided by the radius of curvature.

a = v² / r

Given v = 10 m/s and r = 4 m:

a = (10 m/s)² / 4 m

a = 25 m/s²