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Studentka2010 [4]
3 years ago
13

Rock a is dropped from a cliff and rock b is thrown upward from the same position on the cliff.

Physics
1 answer:
Oksanka [162]3 years ago
4 0

In the A case, v0=0, in the B case v0 >0, so v is greater in the B case. In other words, v is related to the kinetic energy, since the rock B has a larger kinetic energy in the beginning, it also has a larger kinetic energy (larger velocity) in the end.

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Acoustics is the study of sound. In large rooms, such as theaters where large orchestras perform, cushioned seats and carpeted f
stiv31 [10]

Answer:

soundproofing or absorbing

Explanation:

Acoustics is the study of waves, vibrations and sound and its most common applications lie in the sound and noise control industries. Acoustic protection is the application of soft and porous material to protect individuals against undesirable sounds and noises.

cushioned seats and carpeted floors are used in soundproofing to block the unwanted noise and sound.

The Cheapest Ways To Soundproof A Room

1. Rugs:

Rugs make excellent vibration dampeners.

2. Weather Stripping:

If you know that sound is getting into your room via the door or the windows then a very cheap and effective solution can be to use weather stripping.

3. Blankets.

4. Curtains.

5. Egg Cartons.

Homemade Soundproofing Panels

8 0
3 years ago
A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
2 years ago
If it takes 726 watts of power to move a mass 36 meters in 14 seconds, then what is the magnitude of the object’s mass?
Colt1911 [192]

Answer:

20.2

Explanation: Divide 726/34 and you get 20.16 round it and you get 20.2

4 0
2 years ago
How much work is done when you lift a 5kg bag of groceries 1.5 m?
olga55 [171]

Answer:

7.5J

Explanation:

5x1.5=7.5

8 0
3 years ago
A space probe is fired as a projectile from the Earth's surface with an initial speed of 2.05 104 m/s. What will its speed be wh
Elanso [62]

Answer:

The value is  v  =  2.3359 *10^{4} \ m/s

Explanation:

From the question we are told that

  The  initial speed is u =  2.05 *10^{4} \  m/s

 Generally the total energy possessed by the space probe when on earth is mathematically represented as

             T__{E}} =  KE__{i}} +  KE__{e}}

Here  KE_i is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

          KE_i =   \frac{1}{2}  *  m  *  u^2

=>       KE_i =   \frac{1}{2}  *  m  *  (2.05 *10^{4})^2

=>       KE_i =  2.101 *10^{8} \ \ m \ \ J

And  KE_e is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

       KE_e =  \frac{1}{2}  *  m *  v_e^2

Here v_e is the escape velocity from earth which has a value v_e =  11.2 *10^{3} \  m/s

=>    KE_e =  \frac{1}{2}  *  m *  (11.3 *10^{3})^2

=>    KE_e =  6.272 *10^{7} \  \  m  \ \   J

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

        KE_p =  \frac{1}{2}  *  m *  v^2

Generally from the law energy conservation we have that

        T__{E}} =  KE_p

So

       2.101 *10^{8}  m  +  6.272 *10^{7}  m  =   \frac{1}{2}  *  m *  v^2

=>     5.4564 *10^{8} =   v^2

=>     v =  \sqrt{5.4564 *10^{8}}

=>     v  =  2.3359 *10^{4} \ m/s

4 0
2 years ago
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