All categories

2 years ago

How can light interact with wood

Physics

1 answer:

mr_godi [17]2 years ago

7 0

Answer:

Light interacts with wood through it's particle nature.

Explanation:

LIGHT has dual nature properties . It behaves with waves as a wave and with particles as a particle .

Light can interact with matter in three ways: absorption, transmission, and reflection.

ABSORPTION :

When a light wave with a identical frequency to an electron’s natural frequency “impinges” upon an atom, the electrons will begin to vibrate as a result .
The electrons will absorb the light wave and turn it into a vibrational motion . The electrons, in turn, bump up against neighboring atoms, which changes the vibrations intothermal energy .
This thermal energy is not turned back into light energy, thus that particular light wave never leaves the object again. This is ABSORPTION.

2. REFLECTION :

This occurs when the frequency of the incoming light wave does not match that of the electrons’ natural frequency.
If the object is opaque , the electron vibrations are not “passed down” like during absorption.
Rather, the surface-level electrons vibrate briefly before emitting that wave back out (as light). This is REFLECTION.

3. TRANSMISSION :

Transmission works along the same lines as reflection, except it involves transparent or semi-transparent objects.
The atoms taken in the wave, vibrate briefly (but at a small amplitude) , transfer the vibrations throughout the body of the material, and then re-emit the wave as light out the other end. This is TRANSMISSION.

You might be interested in

A 43.9-g piece of copper (CCu= 0.385 J/g°C) at 135.0°C is plunged into 254 g of water at 39.0°C. Assuming that no heat is lost t

Semmy [17]

Answer:

$T = 40.501\,^{\textdegree}C$

Explanation:

The interaction of the piece of copper and water means that the first one need to transfer heat in order to reach a thermal equilibrium with water. Then:

$-Q_{out,Cu} = Q_{in,H_{2}O}$

After a quick substitution, the expanded expression is:

$-(43.9\,g)\cdot (0.385\,\frac{J}{g\cdot ^{\textdegree}C} )\cdot (T-135^{\textdegree}C) = (254\,g)\cdot (4.187\,\frac{J}{g\cdot ^{\textdegree}C} )\cdot (T-39\,^{\textdegree}C)$

$-16.902\,\frac{J}{^{\textdegree}C}\cdot (T-135^{\textdegree}C) = 1063.498\,\frac{J}{^{\textdegree}C} \cdot (T-39^{\textdegree}C)$

$43758,192\,J = 1080.4\,\frac{J}{^{\textdegree}C}\cdot T$

The final temperature of the system is:

$T = 40.501\,^{\textdegree}C$

8 0

2 years ago

Read 2 more answers

All of the following are shaped by learned behavior except __________. A. shyness B. blinking C. biting one’s nails D. angry res

Dvinal [7]

Blinking, that’s an involuntary behavior

7 0

2 years ago

Read 2 more answers

Have you ever written a bio-data or an application letter? Share your experience in the

Georgia [21]

Answer:

I found the experience tasking

Explanation:

I wouldn't say it was hard, neither was it easy. I'd rather go for something like it being tasking. It's worthy of note that it was my first time, and I think it's very normal especially when one hasn't been doing something of that nature previously. Of course I did my draft, which unsurprisingly happened to be not good enough, and I had to look for templates to guide me through the acceptable way.

I still did it in my own way, but in the right way. Ever since then though, I have never stuttered when writing application letters, as it had since then seem inborn

8 0

3 years ago

Which condition is required for Coulomb's law to hold true?

AleksAgata [21]

The correct answer is:
Point charges must be in a vacuum.

In fact, the usual form for of the Coulomb's law is:
 $F= \frac{1}{4 \pi \epsilon_0} \frac{q_1 q_2}{r^2}$
where
 $\epsilon_0$ is the permittivity of free space
q1 and q2 are the two charges
q is the separation between the two charges

However, this formula is valid only if the charges are in vacuum. If they are in a material medium, the law is modified as follows:
 $F= \frac{1}{4 \pi \epsilon_0 \epsilon_r} \frac{q_1 q_2}{r^2}$
where $\epsilon_r$ is the relative permittivity, which takes into account the dielectric effects of the material.

7 0

2 years ago

If a young protostar with a disk is rotating and shrinking. how much faster is it rotating after its size has decreased by a fac

maks197457 [2]

In this system we have the conservation of angular momentum: L₁ = L₂
We can write L = m·r²·ω

Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂

The mass stays constant, therefore it cancels out, and we can solve for ω₂:
ω₂ = (r₁/ r₂)² · ω₁

Since we know that r₁ = 4r₂, we get:
ω₂ = (4)² · ω₁
= 16 · ω₁

Hence, the protostar will be rotating 16 times faster.

5 0

3 years ago