All categories

3 years ago

How can light interact with wood

Physics

1 answer:

mr_godi [17]3 years ago

7 0

Answer:

Light interacts with wood through it's particle nature.

Explanation:

LIGHT has dual nature properties . It behaves with waves as a wave and with particles as a particle .

Light can interact with matter in three ways: absorption, transmission, and reflection.

ABSORPTION :

When a light wave with a identical frequency to an electron’s natural frequency “impinges” upon an atom, the electrons will begin to vibrate as a result .
The electrons will absorb the light wave and turn it into a vibrational motion . The electrons, in turn, bump up against neighboring atoms, which changes the vibrations intothermal energy .
This thermal energy is not turned back into light energy, thus that particular light wave never leaves the object again. This is ABSORPTION.

2. REFLECTION :

This occurs when the frequency of the incoming light wave does not match that of the electrons’ natural frequency.
If the object is opaque , the electron vibrations are not “passed down” like during absorption.
Rather, the surface-level electrons vibrate briefly before emitting that wave back out (as light). This is REFLECTION.

3. TRANSMISSION :

Transmission works along the same lines as reflection, except it involves transparent or semi-transparent objects.
The atoms taken in the wave, vibrate briefly (but at a small amplitude) , transfer the vibrations throughout the body of the material, and then re-emit the wave as light out the other end. This is TRANSMISSION.

You might be interested in

The Venn diagram shown below compares the nuclear reactions in the sun and nuclear power plants.

inessss [21]

Answer:

In nuclear physics and nuclear chemistry, nuclear fission is a nuclear reaction or a radioactive deficiency process in which the nucleus of an atom split into 2 smaller, lighter nuclei.

7 0

4 years ago

Read 2 more answers

why people change their way of being They can be temporary or permanent changes. Other reasons why people change their attitudes

Svetach [21]

Answer:

studies show that our brains are faster at processing opinions we agree with. a crisis is enough to change an attitude about something because a person isn't looking from the outside and is actually experiencing it firsthand which will change them

8 0

4 years ago

At t = 0 the end you are oscillating is at its maximum positive displacement and is instantaneously at rest. Write an equation f

vovikov84 [41]

Answer:

The equation of displacement is $y=A\sin(\omega t-2.50 k+\dfrac{\pi}{2})$ .

Explanation:

Given that,

Distance = 2.50 m

We need to calculate the equation of wave

Using general equation of wave

$y=A\sin(\omega t-kx+\phi)$ ....(I)

Where, A = amplitude

t = time

x = displacement

$\phi$ = phase difference

Put the value in the equation

At t = 0, x = 0, y =A

$A=A\sin(0+\phi)$

$\sin\phi=1$

$\phi=\dfrac{\pi}{2}$

From equation (I)

$y=A\sin(\omega t-2.50 k+\dfrac{\pi}{2})$

Hence, The equation of displacement is $y=A\sin(\omega t-2.50 k+\dfrac{\pi}{2})$ .

7 0

3 years ago

The critical angle for a substance is measured at 53.7 degrees. light enters from air at 45.0 degrees. at what angle it will con

faust18 [17]

When light travels from a medium with greater refractive index $n_1$ to a medium with smaller refractive index $n_2$ , there exists an angle (called critical angle) above which the light is totally reflected, and the value of this angle is given by
$\theta_c = \arcsin ( \frac{n_2}{n_1} )$
In this problem, we know that the critical angle is $\theta_c = 53.7^{\circ}$ , so we can find the ratio between the refractive indices of the two mediums:
$\frac{n_2}{n_1} = \sin \theta_c = \sin 53.7^{\circ} =0.81$
and since the second medium is air (n=1.00), the refractive index of the first medium is
$n_1= \frac{n_2}{0.81}= \frac{1.00}{0.81}=1.23$

In the second part of the problem, we have light entering from air ( $n_i = 1.00$ ) at angle of incidence of $\theta_i = 45.0 ^{\circ}$ , into the second medium with $n_r = 1.23$ . By using Snell's law, we can find the angle of refraction of the light inside the medium:
$n_i \sin \theta_i = n_r \sin \theta_r$
$\sin \theta_r = \frac{n_i}{n_r} \sin \theta_i = \frac{1.00}{1.23} \sin 45^{\circ}=0.574$
$\theta_r = \arcsin(0.574)=35.1^{\circ}$

3 0

3 years ago

If a Ferrari, with an initial velocity of 10m/s, accelerates at at rate of 50m/s/s for 3 seconds, what will its final velocity b

seraphim [82]

Answer:

160 m/s

Explanation:

The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by

$v(t)= u +at$

where

u = 10 m/s

a = 50 m/s^2

If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:

$v(3 s)=10 m/s + (50 m/s^2)(3 s)=160 m/s$

5 0

3 years ago