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andreev551 [17]
2 years ago
11

How can light interact with wood

Physics
1 answer:
mr_godi [17]2 years ago
7 0

Answer:

Light interacts with wood through it's particle nature.

Explanation:

LIGHT has dual nature properties . It behaves with waves as a wave and with particles as a particle .

Light can interact with matter in three ways: absorption, transmission, and reflection.

  1. ABSORPTION :
  • When a light wave with a identical frequency to an electron’s natural frequency “impinges” upon an atom, <em>the electrons will begin to vibrate</em> as a result .
  • The electrons will absorb the light wave and turn it into a vibrational motion . The electrons, in turn, bump up against neighboring atoms, which<em> changes the vibrations intothermal energy</em> .
  • This <em>thermal energy is not turned back into light energy, thus that particular light wave never leaves the object again. This is ABSORPTION. </em>

    2. REFLECTION :

  • This occurs when the <em>frequency of the incoming light wave </em><em>does not match</em><em> that of the electrons’ natural frequency. </em>
  • If the object is opaque , the electron vibrations are not “passed down” like during absorption.
  • Rather, <em>the surface-level electrons vibrate briefly before emitting that wave back out (as light). This is REFLECTION. </em>

    3. TRANSMISSION :

  • Transmission works along the same lines as reflection, except it involves transparent or semi-transparent objects.
  • The atoms taken in the wave, vibrate briefly (but at a small amplitude) , <em>transfer the vibrations throughout the body </em><em>of the material, and then </em><em>re-emit the wave as light out the other end.</em><em> This is TRANSMISSION.</em>
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A photon of red light (wavelength = 710 nm) and a ping-pong ball (mass = 2. 40 × 10^-3 kg) have the same momentum. At what speed
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The speed of the ball moving is

v = 3.94 \times 10 {}^{ - 25}m/s

what is momentum?

The momentum p of a classical object of mass m and velocity v is given by pclassical =mv.

For photons with wavelength λ,this equation does not hold.Instead, the momentum of the Photon is given by p Photon = h/λ

where,h is the planck's constant.

The momentum of the red Photon is

given:

h = 6.626 \times 10 {}^{ - 34}kgm {}^{2}/s(plancks \: constant)

λ = 700 \times 10 {}^{ - 9} m(photons \: wavelength)

p \: photons =  \frac{6.626 \times 10 {}^{ - 34}kgm {}  ^{2}/s }{700 \times 10 {}^{ - 9}m  }

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since,the Photon and the ping-pong ball have the same momentum,we have

pball = pphotons =  \frac{6.626 \times 10 {}^{ - 34}kgm/s  }{700 \times 10 {}^{ - 9} }

pball = mv,m = 2.40 \times 10 {}^{ - 3}kg

v = 3.94 \times 10 {}^{ - 25} m/s

Therefore, if the red photon and the ping-pong ball have the same momentum, the ping-pong ball must have a speed of approximately

v = 3.94 \times 10 {}^{ - 25}m/s

learn more about momentum of photon from here: brainly.com/question/28197406

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