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andreev551 [17]
3 years ago
11

How can light interact with wood

Physics
1 answer:
mr_godi [17]3 years ago
7 0

Answer:

Light interacts with wood through it's particle nature.

Explanation:

LIGHT has dual nature properties . It behaves with waves as a wave and with particles as a particle .

Light can interact with matter in three ways: absorption, transmission, and reflection.

  1. ABSORPTION :
  • When a light wave with a identical frequency to an electron’s natural frequency “impinges” upon an atom, <em>the electrons will begin to vibrate</em> as a result .
  • The electrons will absorb the light wave and turn it into a vibrational motion . The electrons, in turn, bump up against neighboring atoms, which<em> changes the vibrations intothermal energy</em> .
  • This <em>thermal energy is not turned back into light energy, thus that particular light wave never leaves the object again. This is ABSORPTION. </em>

    2. REFLECTION :

  • This occurs when the <em>frequency of the incoming light wave </em><em>does not match</em><em> that of the electrons’ natural frequency. </em>
  • If the object is opaque , the electron vibrations are not “passed down” like during absorption.
  • Rather, <em>the surface-level electrons vibrate briefly before emitting that wave back out (as light). This is REFLECTION. </em>

    3. TRANSMISSION :

  • Transmission works along the same lines as reflection, except it involves transparent or semi-transparent objects.
  • The atoms taken in the wave, vibrate briefly (but at a small amplitude) , <em>transfer the vibrations throughout the body </em><em>of the material, and then </em><em>re-emit the wave as light out the other end.</em><em> This is TRANSMISSION.</em>
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Answer:

Uncorrected values for

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R = 2.4 ohm

Corrected values

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R = 12 OHM

For circuit Q

R = 2.3 ohm

Explanation:

Given data:

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UNCORRECTED VALUES FOR

1) circuit P

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2) circuit Q

I\times (R+0.1) =V

R+0.1 =\frac{6}{2.5}

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