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3 years ago

How can light interact with wood

Physics

1 answer:

mr_godi [17]3 years ago

7 0

Answer:

Light interacts with wood through it's particle nature.

Explanation:

LIGHT has dual nature properties . It behaves with waves as a wave and with particles as a particle .

Light can interact with matter in three ways: absorption, transmission, and reflection.

ABSORPTION :

When a light wave with a identical frequency to an electron’s natural frequency “impinges” upon an atom, the electrons will begin to vibrate as a result .
The electrons will absorb the light wave and turn it into a vibrational motion . The electrons, in turn, bump up against neighboring atoms, which changes the vibrations intothermal energy .
This thermal energy is not turned back into light energy, thus that particular light wave never leaves the object again. This is ABSORPTION.

2. REFLECTION :

This occurs when the frequency of the incoming light wave does not match that of the electrons’ natural frequency.
If the object is opaque , the electron vibrations are not “passed down” like during absorption.
Rather, the surface-level electrons vibrate briefly before emitting that wave back out (as light). This is REFLECTION.

3. TRANSMISSION :

Transmission works along the same lines as reflection, except it involves transparent or semi-transparent objects.
The atoms taken in the wave, vibrate briefly (but at a small amplitude) , transfer the vibrations throughout the body of the material, and then re-emit the wave as light out the other end. This is TRANSMISSION.

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A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the

Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

$U=\dfrac{1}{2}kx^2$ ...(I)

Using gravitational potential energy

$U' =mgh$ ....(II)

Using energy of conservation

$E_{i}=E_{f}$

$U_{i}+U'_{i}=U_{f}+U'_{f}$

$\dfrac{1}{2}kx^2+0=0+mgh$

$h=\dfrac{kx^2}{2mg}$

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

$h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}$

$h=11.653\ m$

Hence, The maximum height above the point of release is 11.653 m.

3 0

3 years ago

Suppose a plot of inverse wavelength vs frequency has slope equal to 0.119, what is the speed of sound traveling in the tube to

strojnjashka [21]

Answer:

8.40 m/s

Explanation:

Slope of the plot is 0.119

Slope of a plot is given by the change in y direction divided by the change in x direction

Here, the y axis represents inverse wavelength and the x axis represents frequency.

f = Frequency (Hz, assumed)

v = Phase velocity (m/s, assumed)

λ = Wavelength (m, assumed)

So, slope

$m=\frac{\frac{1}{\lambda}}{f}$

Now,

$\lambda=\frac{v}{f}\\\Rightarrow \lambda^{-1}=\frac{f}{v}$

$\\\Rightarrow m=\frac{\frac{f}{v}}{f}\\\Rightarrow 0.119=\frac{1}{v}\\\Rightarrow v=\frac{1}{0.119}\\\Rightarrow v=8.40\ m/s$

The speed of sound travelling in the tube is 8.40 m/s

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4 years ago

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It can hurt and harm the body on many different and levels

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4 years ago

Read 2 more answers

To convert minutes per second into kilometre per hour we multiply the speed with

ankoles [38]

Answer:

To convert m/sec into km/hr, multiply the number by 18 and then divide it by 5.

Explanation:

please mark as brainliest

3 0

3 years ago

A student hangs a weight on a newtonmeter. The energy currently stored in the spring in the newton meter is 0.045N. The student

castortr0y [4]

Answer:

5x10^-3

Explanation:

Hooke's Law states that the force needed to compress or extend a spring is directly proportional to the distance you stretch it.

Hooke's Law can be represented as

where F is the force

k is the spring constant

x is the extension of the material

Plug values in the equation

Step 1 find the original extension

0.045 = (400)x

x = 1.125x 10^-4 m d

Step 2 find the new extension

0.045+2 = 400(x)

2.045 = 400x

x = 5.1125x10^-3

Step 3 subtract the new extension with original

Total extension of the spring = 5.1125x10^-3 - 1.125x 10^-4 m = 5x10^-3

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3 years ago