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34kurt
3 years ago
12

Please help on this one? :)

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Formula: Fc=mv^2/r

Fc = centripetal force = to be determined  

m = mass of the car = 1,150 kg  

r = radius of the circle in which the car is traveling = 44 m  

v = linear velocity of the car = 13 m/s

Fc= 1150*(13^2)/44

Fc= 4417.045

Hope this helps!

Good luck! :)

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The drawing shows a large cube (mass = 28.6 kg) being accelerated across a horizontal frictionless surface by a horizontal force
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Answer:

P= 454.11 N

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Since P is the only horizontal force acting on the system, it can be defined as the product of the acceleration by the total mass of the system (both cubes).

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The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:

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In order for the small cube to not slide down, the friction force must equal the weight of the small cube:

3.053*\frac{P}{32.9} = 4.3 * g\\\\P = \frac{4.3*9.8*32.9}{3.053} \\P= 454.11 N

The smallest magnitude that P can have in order to keep the small cube from sliding downward is 454.11 N

8 0
3 years ago
A car accelerates from 4 meters/second to 16 meters/second in 4 seconds. The car’s acceleration is __meters/second2.
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6 0
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sp2606 [1]
From the question,
u = 0m {s}^{ - 1}
v = 6m {s}^{ - 1}

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Ft =m(v-u)


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This implies that

36.0 = 6m
m =  \frac{36.0}{6.0}
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You can also use the equation of linear motion,
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a = 2 {ms}^{ - 2}
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\therefore \: m = 6kg
4 0
3 years ago
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