Answer:
= 3521m/s
The tangential speed is approximately 3500 m/s.
Explanation:
F = m * v² ÷ r
Fg = (G * M * m) ÷ r²
(m v²) / r = (G * M * m) / r²
v² = (G * M) / r
v = √( G * M ÷ r)
G * M = 6.67 * 10⁻¹¹ * 5.97 * 10²⁴ = 3.98199 * 10¹⁴
r = 32000km = 32 * 10⁶ meters
G * M / r = 3.98199 * 10¹⁴ ÷ 32 * 10⁶
v = √1.24 * 10⁷
v = 3521.36m/s
The tangential speed is approximately 3500 m/s.
Answer:
elastic collision
An elastic collision occurs when the two objects "bounce" apart when they collide. Two rubber balls are a good example. In an elastic collision, both momentum and kinetic energy are conserved. Almost no energy is lost to sound, heat, or deformation.
I hope it's helpful!
To solve the problem it is necessary to apply conservation of the moment and conservation of energy.
By conservation of the moment we know that

Where
M=Heavier mass
V = Velocity of heavier mass
m = lighter mass
v = velocity of lighter mass
That equation in function of the velocity of heavier mass is

Also we have that 
On the other hand we have from law of conservation of energy that

Where,
W_f = Work made by friction
KE = Kinetic Force
Applying this equation in heavier object.






Here we can apply the law of conservation of energy for light mass, then

Replacing the value of 

Deleting constants,


Answer:
raise it as high as he can
Explanation: