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qaws [65]
3 years ago
13

Which of the following correctly identifies and explains the charge on an atom of sodium?

Chemistry
1 answer:
likoan [24]3 years ago
7 0

Answer:

The best and most correct answer among the choices provided by your question is the fourth choice.

The data explains that sodium atoms hardly ever form 2+ ions.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

Explanation:

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Answer:

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Explanation:

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6 0
3 years ago
Some safety precautions people should take when using fireworks
Lilit [14]

Answer:

Do not try to re-light or handle malfunctioning fireworks. Soak both spent and unused fireworks in water for a few hours before discarding.

3 0
3 years ago
Evaluate importance:<br> - Why does a patch of garbage in the ocean effect humans on land?
andrew-mc [135]

Why does a patch of garbage in the ocean effect humans on land

3 0
2 years ago
A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa. If Po2 =
HACTEHA [7]

Answer:

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.

<u>The pressure for oxygen is 3 kPa</u>

Explanation:

According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

P_{total}=P_{1}+P_{2}+P_{3}

So,

For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:

P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}

P_{total} = 32.5kPa

P_{O_{2}} = 6.5kPa

P_{N_{2}} = 23.0kPa

Insert the values in :

P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}

32.5 kPa = 6.5 kPa + 23.0 kPa +P_{CO_{2}}

32.5 kPa = 29.5 kPa +P_{CO_{2}}

P_{CO_{2}}= 32.5 - 29.5

P_{CO_{2}}= 3kPa

6 0
3 years ago
I can’t find the answer, can you help me please?
Tatiana [17]

Answer: Warm ocean air then rises into the storm, then forming an area of low pressure underneath. :)

Explanation:

7 0
2 years ago
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