Ask question

Ask question

All categories

4 years ago

15

In one year, a large tree can remove from the air the same amount of carbon dioxide produced by a car travelling 500 miles. If N

ew York City contains approximately 600,000 trees, how many miles of a car traffic can trees clean in a year?

1 answer:

marissa [1.9K]4 years ago

7 0

I am so sure it's 600,000 x 500 so you get 300,000,000

You might be interested in

in a lab, resonance tubes are used to determine experimentally the speed of sound. using the data given, evaluate the best appro

jek_recluse [69]

The approximate speed of sound is about 761 mph or 335.28 meters/second.

<h3>What's the approximate speed of sound?</h3>

If we consider the normal atmosphere at sea level, the speed of sound is about 761 mph or 335.28 meters/second. The speed of sound is different in different mediums such as solid and liquid.

So we can conclude that the approximate speed of sound is about 761 mph or 335.28 meters/second.

Learn more about speed here: brainly.com/question/4931057

#SPJ1

3 0

2 years ago

A car has the velocity of 2.35 after 4.67 it's velocity is 9.89 what is the average acceleration

kiruha [24]

Average acceleration = (change in speed) / (time for the change) .

Change in speed = (ending speed) - (beginning speed)

=  (9.89 miles/hour) - (2.35 yards/second) = 26,839.2 ft/hr

Acceleration = (26,839.2 ft/hr) / (4.67 days) = 2,873.58 inch/hour²

6 0

3 years ago

The blades of a fan running at low speed turn at 26.2 rad/s. When the fan is switched to high speed, the rotation rate increases

Lady bird [3.3K]

Answer: $1.79\ rad/s^2$

Explanation:

Given

Initial angular speed is $\omega_1=26.2\ rad/s$

Final angular speed is $\omega_2=36.5\ rad/s$

Time period $t=5.75\ s$

Magnitude of the fan's acceleration is given by

$\Rightarrow \alpha=\dfrac{\omega_2-\omega_1}{t}$

Insert the values

$\Rightarrow \alpha=\dfrac{36.5-26.2}{5.75}\\\\\Rightarrow \alpha=\dfrac{10.3}{5.75}\\\\\Rightarrow \alpha=1.79\ rad/s^2$

Thus, fan angular acceleration is $1.79\ rad/s^2$

8 0

3 years ago

Read 2 more answers

Bill is farsighted and has a near point located 119 cm from his eyes. Anne is also farsighted, but her near point is 70.0 cm fro

Gennadij [26K]

Answer:

Explanation:

For Bill's glasses)

d_o=25 cm-2 cm=23.2 cm

d_i=129 cm-2 cm=127 cm

We know that

$1 / f = 1 / d_o + 1 / d_i
$

$f=(1 / d_o + 1 / d_i)^-1
$

so plug the numbers in

$f = (1 / (23) + 1 / (127))^-1
$

= 28.08 cm

For Anna's glasses)

d_o=25 cm-2 cm=23 cm

d_i=70.0 cm-2 cm=68 cm

Same thing

$(1 / f = 1 / d_o + 1 / d_i
)$

$f=(1 / do + 1 / di)^-1
$

so plug the numbers in

$f = (1 / (23) + 1 / (68))^-1
$

= 17.21 cm

5 0

3 years ago

What is avarage speed? (AS)<br>speed?

Artist 52 [7]

Answer:

average speed = total distance/total time

6 0

4 years ago

Read 2 more answers