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3 years ago

A projectile lands at the same height from which it was launched. which initial velocity will result

1 answer:

5 0

The required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

First, we must understand that the component of the velocity along the vertical is due to maximum height achieved and expressed as usin θ.

The component of the velocity along the horizontal is due to the range of the object and is expressed as ucosθ.

If the <u>air resistance is ignored</u>, the velocity of the object will be constant throughout the flight and the initial velocity will be equal to the final velocity.

Hence the required initial velocity that will result if a projectile lands at the same height from which it was launched is V₀ = V cosθ

Learn more here; brainly.com/question/12870645

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Describe the relationship between input force, output force,<br>and load force.

g100num [7]

Answer: the relationship between the input force and output force is that, Input Force represents the amount of force that you put into another object (which is considered as the load force) while Output Force represents the force that a specific object has as a result of the input force.

Explanation:

Using a lever as an example, a broom is a lever used to sweep floors, the input force is applied by one of the arm used in sweeping, while the output force is on the other edge of the broom (broom tip)

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3 years ago

Meg goes swimming on a hot afternoon. When she comes out of the pool, her foot senses that the prevement is unbearably hot. Supp

mart [117]

1.Record her observation with the time it was hot.
2. Gather info about the pavement and its surroundings. Find out what it's made of and what its temp. is at different times of the day.
3. Come up with a hypothesis about why it is hot.
4. Design an experiment to test the hypothesis. If she thinks the Sun is responsible (which she should b smart enough to know), keep it covered during the day time and check it's temp.
5. Come up with a conclusion. If her hypothesis is not supported, design a new experiment or gather more info.

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3 years ago

What are the two factors that determine the amount of gravitational force between two objects?

melisa1 [442]

Answer:

The mass of the objects

Distance between the objects

Explanation:

The two factors that determines the amount of gravitational force between two objects is the mass of the objects and the distance between them.

Gravitational force of attraction is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them. This is the postulate of the newton's law of universal gravitation.

Mathematically:

F = $\frac{Gm_{1}m_{2} }{r^{2} }$

m is the mass

r is the distance

G is the universal gravitation constant

6 0

3 years ago

A 0.58 kg mass is moving horizontally with a speed of 6.0 m/s when it strikes a vertical wall. The mass rebounds with a speed of

Sunny_sXe [5.5K]

Answer:

$5.8\; {\rm kg\cdot m \cdot s^{-1}}$ .

Explanation:

If the mass of an object is $m$ and the velocity of that object is $v$ , the linear momentum of that object would be $m\, v$ .

Assume that the initial velocity of the mass is positive ( $6.0\; {\rm m\cdot s^{-1}}$ .) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be $(-4.0\; {\rm m\cdot s^{-1}})$ .

Thus, the change in the velocity of the mass would be:

$\begin{aligned}& (\text{Change in Velocity}) \\ =\; & (\text{Final Velocity}) - (\text{Initial Velocity}) \\ =\; & (-4.0\; {\rm m\cdot s^{-1}}) - (6.0\; {\rm m\cdot s^{-1}}) \\ =\; & (-10\; {\rm m\cdot s^{-1})\end{aligned}$ .

The change in the linear momentum of the mass would be:

$\begin{aligned} & \text{change in momentum} \\ =\; & (\text{mass}) \times (\text{change in velocity}) \\ =\; & 0.58\; {\rm kg} \times (-10\; {\rm m\cdot s^{-1}}) \\ =\; & (-5.8\; {\rm kg \cdot m \cdot s^{-1}})\end{aligned}$ .

Thus, the magnitude of the change of the linear momentum would be $5.8\; {\rm kg \cdot m \cdot s^{-1}}$ .

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3 years ago

A block of mass m attached to a horizontally mounted spring with spring constant ???? undergoes simple harmonic motion on a fric

Firdavs [7]

Answer:

(E) It would increase by a factor of 2.

Explanation:

Maximum speed (v) is given by:

$v = \omega *A$

Where ω is the angular frequency and A is the amplitude.

The angular frequency of a spring-mass system is given by:

$\omega = \sqrt{\frac{k}{m}}$

Where k is the spring constant and m is the mass of the block attached to the spring.

Therefore, maximum speed can be written as:

$v= A\sqrt{\frac{k}{m}}\\$

Since mass and amplitude are constant values, a relationship between maximum velocity and spring constant can be defined as:

$v =C \sqrt{k}$

There is a linear relationship between maximum velocity and the square root of the spring constant. Therefore if the spring constant is increased by a factor of 4, the velocity is increased by a factor of the square root of 4, which is 2.

The answer is (E) It would increase by a factor of 2.

8 0

3 years ago