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3 years ago

How many L are required to make 3.5 M hydrochloric acid using 1.1 moles?

Chemistry

1 answer:

ch4aika [34]3 years ago

4 0

<h3>Answer:</h3>

0.31 L

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS
Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Chemistry

Atomic Structure

Moles

Aqueous Solutions

Molarity = moles of solute / liters of solution

Equilibrium - Acid/Base

Strong Acids
Weak Acids
Writing Acids

<h3>Explanation:</h3>

Step 1: Define

[Given] 3.5 M HCl

[Given] 1.1 moles

[Solve] Liters solution

Step 2: Solve

Substitute in variables [Molarity]: $\displaystyle 3.5 \ M = \frac{1.1 \ moles}{x \ L}$
[Solution] Cross-Multiply [Equality Property]: $\displaystyle x \ L = \frac{1.1 \ mol}{3.5 \ M}$
[Solution] Divide: $\displaystyle x = 0.314286 \ L$

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs.

0.314286 L ≈ 0.31 L

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___________ polymers can be produced in large quantities at low cost. please. thank you.

MA_775_DIABLO [31]

Answer:

Plastic polymers

Explanation:

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When hear is applied plastics gets soft and can be molded into different forms and then it becomes hardened after exposure to air(dried).

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3 years ago

Why doesn't gold react with oxygon

lara31 [8.8K]

Give me a thanks I been helped a lot of people and non of them is thanks me.

Gold have a single outer electron. This seems disadvantageous, energy-wise, until you look at the orbitals the electrons are in. The lone electron is in an S-orbital. This orbital is thus half full (since s-orbitals can contain 2 electrons), whereas all the other inner orbitals in silver and gold are filled, and hence exceptionally stable. After a full orbital, the next most stable orbital is a half full one.

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3 years ago

Perform the following operation

Yanka [14]

Taking into account the scientific notation, the result of the sum is 10.84300×10³.

Scientific notation

First, remember that scientific notation is a quick way to represent a number using powers of base ten.

The numbers are written as a product:

a×10ⁿ

where:

a is a real number greater than or equal to 1 and less than 10, to which a decimal point is added after the first digit if it is a non-integer number.
n is an integer, which is called an exponent or an order of magnitude. Represents the number of times the comma is shifted. It is always an integer, positive if it is shifted to the left, negative if it is shifted to the right.

Sum in scientific notation

You want to add two numbers in scientific notation. It should be noted that when the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found. In this case, the highest exponent is 3.

Then all the values are expressed as a function of the base 10 exponent with the highest exponent. In this case: 9.7300×10²= 0.97300×10³

Taking the quantities to the same exponent, all you have to do is add what was previously called the number "a". In this case:

0.97300×10³ + 9.8700×10³= (0.97300+ 9.8700)×10³= 10.84300×10³

Finally, the result of the sum is 10.84300×10³.

Learn more:

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2 years ago

A solution of H2SO4(aq) with a molal concentration of 4.80 m has a density of 1.249 g/mL. What is the molar concentration of thi

Naddika [18.5K]

Imagine we have mass of solvent 1kg (1000g)
According to that: $molality =n(solute) / m(solvent) =\ \textgreater \ 4.8m = 4.8mole / 1kg$
= 4.8 mole * 98 g/mole = 470g
$m(H2SO4) = n(H2SO4)*Mr(H2SO4) =\ \textgreater \$ $=\ \textgreater \ Molarity = 4.8 mole / 1.2 L = 4 M$ m(H2SO4) which is =470g

m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =>
$Molarity = n(solute) / V(solution) =\ \textgreater \$

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3 years ago

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Kobotan [32]

Answer:

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Explanation:

3 0

2 years ago

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