Answer : The volume of carbon dioxide produced, 6.0 L
Solution : Given,
Volume of oxygen = 3.0 L
First we have to calculate the moles of oxygen.
At STP, 1 mole of gas contains 22.4 L volume of gas.
As, 22.4 L volume of oxygen obtained from 1 mole of oxygen gas
As, 3.0 L volume of oxygen obtained from
moles of oxygen gas
Now we have to calculate then moles of carbon dioxide.
The balanced chemical reaction will be,
![2CO(g)+O_2(g)\rightarrow 2CO_2(g)](https://tex.z-dn.net/?f=2CO%28g%29%2BO_2%28g%29%5Crightarrow%202CO_2%28g%29)
From the reaction we conclude that
1 mole of oxygen react to give 2 moles of carbon dioxide
0.1339 mole of oxygen react to give
moles of carbon dioxide
The moles of carbon dioxide gas = 0.267 moles
Now we have to calculate the volume of carbon dioxide.
As, 1 mole of carbon dioxide contains 22.4 L volume of carbon dioxide gas
So, 0.267 mole of carbon dioxide contains
volume of carbon dioxide gas
The volume of carbon dioxide gas = 5.98 L ≈ 6.0 L
Therefore, the volume of carbon dioxide produced, 6.0 L