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2 years ago

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Chemistry

1 answer:

Zielflug [23.3K]2 years ago

3 0

Answer:

Explanation:

Molarity measures the strength of a solution. Remember, a solution is made up of two parts: the solvent (which does the dissolving) and the solute (the substance that is dissolved). The more solute there is, the higher the concentrate and therefore the higher the molarity of the solution. Thus B is the answer

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Is potassium iodide an electrolyte or nonelectrolyte?

Lera25 [3.4K]

Its a strong electrolyte!.

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3 years ago

What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of soluti

puteri [66]

Answer: The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute = $\frac{\text{Given mass}}{\text{Molar mass}}=\frac{10.0g}{162.2g/mol}=0.0616moles$

${V_s}$ = volume of solution in ml = 275 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{0.0616\times 1000}{275ml}=0.224mole/L$

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7 0

3 years ago

___au2s3 ___h2 → ___au ___h2s

liberstina [14]

The best way to balance an equation is to balance one atom at a time.
You start with two Au atoms on the left, so you know the coefficient of Au on the right has to be 2. So at first we get,
Au2S3 + H2 --> 2Au + H2S
Then, notice you have 3 sulfur atoms on the left, so you need three on the right.
Our equation becomes
Au2S3 + H2 --> 2Au + 3H2S
Lastly, we now have six hydrogen atoms on the right, and only two on the left, so we assign a three to the H2 on the left
Au2S3 + 3H2 --> 2Au + 3H2S Is the balanced final equation.

7 0

3 years ago

35 cm3 of a metal has a mass of 121 grams. whats is its density?

dusya [7]

Answer:

The density of the metal is 3.457 g/cm³.

Explanation:

Given,

mass of metal = 121 grams

Volume = 35 cm³.

Density = ?

Density of the metal can be found by using the formula

Density = Mass/Volume

Substituting the values,

Density = 121/35 = 3.457 g/cm³.

5 0

3 years ago

Which of the following aqueous solutions would have the highest boiling point? 3.0 M solution of molecular compound sucrose (C12

Ne4ueva [31]

Answer: option b) 3.0 M solution of ionic compound aluminum chloride (AlCl₃)

Explanation:

1) The solutions given are:

a) 3.0 M solution of molecular compound sucrose (C₁₂H₂₂O₁₁)

b) 3.0 M solution of ionic compound aluminum chloride (AlCl₃)

c) 3.0 M solution of ionic compound lithium bromide (LiBr)

d) 3.0 M solution of ionic compound calcium fluoride (CaF₂)

2) The elevation of the boiling point of a solution is a colligative property.

3) That means that the elevation of the boiling point depends on the number of solute particles in the solvent and not the identity per se of the solute particles.

4) The formula of the elevation of the boiling point, ΔTb is:

ΔTb = i × m × Kb.

Where:

i) i is the Van't Hoof constant and is equal to the number of particles for each molecule or unit formula.

If the compound is a molecule (covalent bond) i = 1, if the compound is ionic, i is the number of ions product of the dissociation (I will show you how to determine it for each of the compounds given).

ii) m is the molality of the solution (moles of solute per kg of solvent)

iii) Kb is the molality boiling constant. It is a constant for every solvent. It does not change with the solute.

4) For our four compounds, m and kb are egual, so you must analyze the i factor for each solution.

a) 3.0 M solution of molecular compound sucrose (C₁₂H₂₂O₁₁)

Since it is a molecular compound it does not dissociate and i = 1

b) 3.0 M solution of ionic compound aluminum chloride (AlCl₃)

Assume the ionic compound dissociates 100%. The for eveary unit of AlCl₃ there will be 4 ions. Those are 4 particles and means that i = 4.

c) 3.0 M solution of ionic compound lithium bromide (LiBr)

Assuming also 100% dissociation of this ionic compound, since every LiBr unit dissociates into two ions, i = 2.

d) 3.0 M solution of ionic compound calcium fluoride (CaF₂)

Following same reasoning, i = 3.

5) Conclusion: since the greatest i factor is 4, and given all the other factors equal, the 3.0 M solution of ionic compound aluminum chloride (AlCl₃), option b, would be the aqueous solutions with the highest boiling point,

8 0

3 years ago

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